Q10 A student wants to raise £100 for charity.
1 answer:
Answer:
He must charge minimum £0.84 for one hot dog.
Step-by-step explanation:
Ingredients cost for hot dogs at the supermarket,
Price of dog sausages tin of 8 = 50p ≈ £0.5
Price of dog bun packs of 6 = 90p ≈ £0.90
Number of tins required for 150 hot dogs = = 6.25
So student will purchase 7 tins.
Cost of 7 tins = 7 × 0.5
= £3.5
Number of dog buns packets required = = 25
Cost of 25 packs = 25 × 0.9
= £22.5
Total cost of the material used for 150 buns = 22.5 + 3.5
= £26.0
Let the selling price of each hot dog = £x
Then selling price of 150 hot dogs = £150x
Students wants the profit = £100
So, Selling price - Cost price = profit
150x - 26 = 100
150x = 126
x =
x = £0.84
Therefore, he must charge minimum £0.84 for one hot dog.
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Weird. A period appears above this... huh.
Answer:
[Th]e cube has a greater value.
Step-by-step explanation:
What the word problem really wants us to get [is ]the question of 'Which is greater, A=6a^2 when 'a' [is] 18 or A=4r^2 when r = 9? And here's how to solve that.
Starting with the[ c]ube we have A=6a^2. A bit t[o]o simple, right?
A=6(18)^2 Substitute numbers.
A=6(324) Solve ex[p]onents.
A=1944 Mult[i]ply.
So w[e] know that the cube is 1944 meters cube[d ] in area. But what about the more [f]ormidable sphere? Fo[r] it we need a slightly m[o]re co[m]plicated formula, A=4r^2. However, instead of using the real pi I will be rounding to 3.14, since we have no calculator so anything more would take way too long and fry your[ bra]in.
A=4(3.14)(9)^2 Subst[i]tute numbers.
A=4(3.14)(81) Solve expone[n]ts.
A=12.56(81) Multip[ly].
A=1017.36 Multiply again[.]
Now, since I'm sure all of us can count, we know that 1944 is greater than 1017.36. Or in other words, the cube is bigger than the sphere.
And PLEASE don't copy this guys. Make your own iteration. Change it up!