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stellarik [79]
3 years ago
7

Q10 A student wants to raise £100 for charity.

Mathematics
1 answer:
ElenaW [278]3 years ago
8 0

Answer:

He must charge minimum £0.84 for one hot dog.

Step-by-step explanation:

Ingredients cost for hot dogs at the supermarket,

Price of dog sausages tin of 8 = 50p ≈ £0.5

Price of dog bun packs of 6 = 90p ≈ £0.90

Number of tins required for 150 hot dogs = \frac{150}{8} = 6.25

So student will purchase 7 tins.

Cost of 7 tins = 7 × 0.5

                      = £3.5

Number of dog buns packets required = \frac{150}{6} = 25

Cost of 25 packs = 25 × 0.9

                            = £22.5

Total cost of the material used for 150 buns = 22.5 + 3.5

                                                                         = £26.0

Let the selling price of each hot dog = £x

Then selling price of 150 hot dogs = £150x

Students wants the profit = £100

So, Selling price - Cost price = profit

150x - 26 = 100

150x = 126

x = \frac{126}{150}

x = £0.84

Therefore, he must charge minimum £0.84 for one hot dog.

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5 0
3 years ago
What is dynamic environment?​
jeka94

Answer:

A dynamic environment is a business environment that is rapidly changing. In a dynamic market, businesses have to adapt quickly to changes and develop new ideas, products and services to keep up with technology and new trends.

Step-by-step explanation:

6 0
2 years ago
3. The following sets are not equal - An (BUC) and AU(BnC) Construct a universe U and non-empty sets A, B, and C so that the abo
yarga [219]

Answer:

1.U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

2.U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

Step-by-step explanation:

We are given that A\cap (B\cup C) and A\cup (B\cap C)

are different sets

1.We have to construct a universe set U and non empty sets A,B and C so that above set in fact the same

Suppose U={1,2,3,4,5}

A={2}

B={2,3}

C={4,5}

B\cap C=\phi

B\cup C={2,3,4,5}

A\cap (B\cup C)={2}\cap{2,3,4,5}={2}

A\cup (B\cap C)={2}\cup\phi={2}

Hence, A\cap (B\cup C)=A\cup (B\cap C)

2.We have to construct a universe set U and non empty sets A,B and C so that  above sets are in fact different

Suppose U={1,2,3,4}

A={1,2}

B={2,3}

C={4}

B\cap C=\phi

B\cup C={2,3,4}

A\cup (B\cap C)={1,2}\cup \phi={1,2}

A\cap (B\cup C)={1,2}\cap {2,3,4}={2}

Hence, A\cap (B\cup C)\neq A\cup (B\cap C)

3 0
3 years ago
Students were packed shoulder to shoulder in a gym for a pep rally. The students were in a rectangular shaped area of 7,500 ft2.
hram777 [196]

Answer: 1527

Step-by-step explanation:

Total Area = 7500 ft^2

Area covered by one student = Area of one circle

                                                   = π*r^2

r = radius of circle = 2.5/2 = 1.25 ft

Area covered by one student = π*1.25^2 = 4.91 ft^2

Number of students who can fit into total area = Total Area/Area covered by one student

Number of students who can fit into total area = 7500/4.91 = 1527.49

Hence the answer is 1527 students

7 0
3 years ago
Kira John and Ryan sent a total of 112 text messages during the weekend. Kira sent 8 fewer messages than Ryan. John sent 4 times
Softa [21]

Answer:

Kirasent 16 and Ryan sent 96

Step-by-step explanation:

I got this because Kira is x-8 and Ryan is 4x. 4x-x-8=112 is equal to 5x=120. So x=24.Kira has 16 when plugging in x and Ryan has 96 because 4 times 24 is 96.

4 0
3 years ago
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