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3 years ago

A top swimmer would be able to swim across a 25-meter pool in about 1/5

Mathematics

1 answer:

Anni [7]3 years ago

7 0

Answer:

125 m/min

Step-by-step explanation:

Find the rate (speed) as follows:

25 meters

--------------------- = (125/1) meters/min = 125 m/min

(1/5) minute

This is equivalent to about 380 ft/min

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Please help me find the answer

MatroZZZ [7]

Answer:

use calculator

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

You are choosing between two health clubs. Club A offers membership for a fee of $ 28$28 plus a monthly fee of $ 20.$20. Club B

eimsori [14]

Answer:

That is to say that at 3 months, the values of the club are equal.

Club A = 268 dollars in total

Club B = 295 dollars in total

Step-by-step explanation:

The first thing is to propose an equation for each club. Let m be the number of months.

Club A = 28 + 20 * m

Club B = 19 + 23 * m

Now, to know when it is the same, we must equal the value of Club A with Club B, it would look like this

28 + 20 * m = 19 + 23 * m

By rearranging the equation we have:

23 * m - 20 * m = 28-19

3 * m = 9

m = 3

That is to say that at 3 months, the values of the club are equal.

Now to know the total value, we will do it with an annual membership, which would be a total of 12 months, therefore it is to replace in the equation of each one:

Club A = 28 + 20 * 12 = 268 dollars in total

Club B = 19 + 23 * 12 = 295 dollars in total

3 0

3 years ago

Mary rode her bike for 2 2/5 miles on Wednesday. On Thursday, she biked 1 1/4 times as far as on Wednesday. How many miles did M

snow_lady [41]

2 2/5=12/5
1 1/4=5/4
12*5=60
5*4=20
60/20=3
So the answer is 3 miles

8 0

3 years ago

Help solving this problem, the second problem not the third

yawa3891 [41]

Given:

1 Van and 4 buses filled with 195 students.

1 Van and 5 buses filled with 241 students.

Let x and y be the number of students in Van and number of students in bus.

$\begin{gathered} x+4y=195\ldots\text{ (1)} \\ x+5y=241\ldots\text{ (2)} \end{gathered}$

Subtract equation (1) from equation (2)

$\begin{gathered} x+5y-x-4y=241-195 \\ y=46 \end{gathered}$

Substitute y=46 in equation (1)

$\begin{gathered} x+4(46)=195 \\ x+184=195 \\ x=195-184 \\ x=11 \end{gathered}$

Number of students that van can carry is 11.

Number of students that bus can carry is 46

7 0

1 year ago

PLEASE HELP!! 48 POINTS!!

Likurg_2 [28]

The exact number is 121.966019, so if you round to the nearest whole number, the answer is 122.

4 0

3 years ago