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kondaur [170]
3 years ago
12

If t=38.5 and s=31.4 find S. Round to the nearest tenth

Mathematics
2 answers:
zubka84 [21]3 years ago
8 0

<u>Answer:</u>

The correct answer option is C. S = 54.6°.

<u>Step-by-step explanation:</u>

We are given a right angled triangle with two known sides, s and t.

We are to find the value of the angle S.

For that, we will use sine.

sin S = \frac { s } { t }

sin S = \frac { 3 1 . 4 } { 3 8 . 5 }

S = sin'0.815

S = 54.6°

Dima020 [189]3 years ago
6 0

Answer: option c.

Step-by-step explanation:

You need to remember the identity:

sin\alpha=\frac{opposite}{hypotenuse}

The inverse of the sine function is arcsine. You need to use this to calculate the angle "S":

 \alpha =arcsin(\frac{opposite}{hypotenuse})

You know that you need to find the measure of "S" and t=38.5 (which is the hypotenuse) and s=31.4 (which is the opposite side), then you can substitute values into   \alpha =arcsin(\frac{opposite}{hypotenuse})

Then, you get:

S=arcsin(\frac{31.4}{38.5})\\\\S=54.6\°

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4x³-2x⁴+8x+10x²-4 in standard form
Andru [333]

Answer:

-2x⁴+4x³+10x²+8x-4

Step-by-step explanation:

Standard form for a polynomial is from highest power to lowest power

4x³-2x⁴+8x+10x²-4

-2x⁴+4x³+10x²+8x-4

7 0
4 years ago
No link please I need a answer
Kryger [21]

Answer: 10

Step-by-step explanation:

We need to find the hypotenuse (the hypotenuse is the diagonal side of a right triangle), so we can use this formula: a^2+b^2=c^2

The two "legs" are a and b (it doesn't matter which leg is a and which leg is b), but the most important thing is that the hypotenuse is c.

So, we now know that we have to solve for c. To solve for c, substitute the values shown in the image for a and b

a^2+b^2=c^2

6^2+8^2=c^2

36+64=c^2

100=c^2

\sqrt{100}=c

c=10

7 0
3 years ago
What is 7.43 rounded to he nearest hundredth
vazorg [7]
<span>What is 7.43 rounded to he nearest hundredth?

still same number

answer:

7.43</span>
4 0
4 years ago
Read 2 more answers
5[x-(4x-5)]=3-8x <br> Solving for x
stiv31 [10]
5(x-4x+5)=3-8x
5x-20x+25=3-8x
-15x+25=3-8x
-7x+25=3
-7x=-22
x= 22/7

7 0
3 years ago
Find the surface area of a regualar pyramid that is a pentagonal pyramid with the area of a base is is 440.4mm and a height of 2
Inessa [10]

Answer:

1240.4 mm²

Step-by-step explanation:

The surface area of a pyramid = Area of the all sides + Area of base

Each side is a triangle.

With a regular pentagonal pyramid, the area of each triangle is

A = \frac{1}{2}\times\text{base}\times\text{slant height}

For the 5 triangles,

A = 5\times\frac{1}{2}\times\text{base}\times\text{slant height} = \frac{1}{2}\times5\times\text{base}\times\text{slant height}

Substituting given values,

A = 5\times\frac{1}{2}\times16\ \text{mm}\times20\ \text{mm} = 800 \text{mm}^2

Area of base = 440.4 mm²

Surface area of a pyramid = 800 + 440.4 mm² = 1240.4 mm²

6 0
3 years ago
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