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sergiy2304 [10]
3 years ago
11

Maria average 81 on her first three History exams. the first score was 83. The second score was 4 less than the third score. Wha

t did she score on the second and third exam​
Mathematics
1 answer:
bogdanovich [222]3 years ago
6 0

Answer:

76 on second exam, 80 on third exam

Step-by-step explanation:

First, find the total of all 3 test scores by multiplying the average by the number of elements. 81 · 3 = 243.

The first score is 83 so 243 - 83 = 160. 160 is the other two test scores combined.

To find the other 2 scores, divide 160 by 2, which is 80.

The second score is 4 less so it will be 76. The third score is 80.

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\begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{gallons of }}{amount}\\ \cline{2-4}&\\ \textit{1st mixture}&5&0.4&\stackrel{(5)(0.4)}{2}\\ \textit{2nd mixture}&3&0.5&\stackrel{(3)(0.5)}{1.5}\\ \cline{2-4}&\\ mixed&8&p&3.5 \end{array} \\\\\\ 8p=3.5\implies p=\cfrac{3.5}{8}\implies p=0.4375\implies p=\stackrel{\%}{43.75}

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