All categories

3 years ago

Major help i will make u brainllest

Mathematics

1 answer:

stealth61 [152]3 years ago

6 0

Answer:

Step-by-step explanation:

Using the Altitude- on- hypotenuse theorem

(leg of big Δ )² = (part of hypotenuse below it ) × ( whole hypotenuse), that is

x² = (30 - 6) × 30 = 24 × 30 = 720 ( take square root of both sides )

x = $\sqrt{720}$ = $\sqrt{144(5)}$ = $\sqrt{144}$ × $\sqrt{5}$ = 12 $\sqrt{5}$ → d

You might be interested in

Please help me with this !! I REALLY need to have good grades because...Back story I had my phone and I broke it and I can't get

nevsk [136]

Answer:

Transformation include reflecting and dilating of points

The scale factor from PQR to P'Q'R' is 1/4

The coordinates of P"Q"R" are P"=(-1,0) Q"=(0,-1) R"=(2,-1) .

PQR and P′'Q′'R′' are not congruent

The points are given as:

p=(4,0)

q=(0,-4)

r=(-8,-4)

p'=(1,0)

q'=(0-1)

r'=(-2,-1)

(a)The scale factor from PQR to P'Q'R

To do this, we make use of corresponding sides QR and Q'R

So, the scale factor (k) is:

k=q'r'/qr

k=2/8

k=1/4

(b) The coordinates of P"Q"R from reflecting P'Q'R' about the y-axis

The rule of this transformation is:

(x,y)--------(-x,y)

So, we have:

p"=(-1,0)

q"=(0,-1)

r"=(2,-1)

No they are not

This is so because

PQR was dilated by 1/4 to get P'Q'R

P'Q'R' and P"Q"R" are congruent

Hence, PQR and P′'Q′'R′' are not congruent

Step-by-step explanation:

4 0

3 years ago

Convert into slope intercept form?

Alexeev081 [22]

<h3>Answer:</h3>

y = 2x + 5

<h3>Step-by-step explanation:</h3>

<u>Definitions</u>:

Slope Intercept form; y = mx + b

m = slope

b = y intercept

Step 1: Since the slope is given plug it into y = mx

y = 2x + b

Step 2: Plug a points' x and y into their corresponding spots to solve for b

(33) = 2(14) + b

Simplify and solve

33 = 28 + b

-28 -28

5 = b

Plug both your slope in and your y intercept into y = mx + b

y = 2x + 5

6 0

3 years ago

Find the sum of 46 + 42 + 38 + ... + (-446) + (-450)46+42+38+...+(−446)+(−450)

JulijaS [17]

sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

<u>Step-by-step explanation:</u>

We need to find sum of sequence : 46 + 42 + 38 + ... + (-446) + (-450)

Given sequence is an AP with following parameters as :

$a=46\\d=42-46=-4$

So , Let's calculate how many terms are there as :

⇒ $a_n=a +(n-1)d$

⇒ $-450=46 +(n-1)(-4)$

⇒ $-496=(n-1)(-4)$

⇒ $\frac{-496}{-4}=n-1$

⇒ $124=n-1$

⇒ $n=125$

Sum of an AP is :

⇒ $S_n = \frac{n}{2}(2a+(n-1)d)$

⇒ $S_1_2_5 = \frac{125}{2}(2(46)+(125-1)(-4))$

⇒ $S_1_2_5 = \frac{125}{2}(-404)$

⇒ $S_1_2_5 =-25,250$

Therefore , sum of sequence Find the sum of 46 + 42 + 38 + ... + (-446) + (-450) is -25,250

3 0

3 years ago

Read 2 more answers

A model car is 8 inches long and 5.2

Sphinxa [80]

Use proportions here - 8/5.2 = 96/width of actual car. using cross multiplication, 5.2*96 = 8x. this gives you 499.2 = 8x. divide both sides by eight to get x=62.4. the width of the actual car is 62.4 inches.

7 0

3 years ago

Pls helppp due soon!!

FrozenT [24]

Answer:

I think the answer is B

Step-by-step explanation:

Sorry if it's wrong

4 0

3 years ago

Read 2 more answers