The confidence interval for the proportion of students attending a football game is [0.6592, 0.7044].
Confidence interval can be calculated by below formula
where the left part is the lower interval and right side is the higher interval.
Pcap = 750/1100
Pcap = 0.6818
Again to calculate 
, as we know that the level of confidence is 90 percent so its value will be 1.645
now putting the values on the both side we can get ,
0.6818 - 1.645 x 0.014 < p < 0.6818 + 1.645 x 0.014
0.6818 - 0.023 < p < 0.6818 + 0.023
0.6588 < p < 0.7048
the nearest value is [0.6592, 0.7044]
Hence the confidence interval for the proportion of students attending a football game is [0.6592, 0.7044]
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<h3>
Answer:</h3>
c. 27 40.5
<h3>
Step-by-step explanation:</h3>
Step 1 is "read and understand the problem." Step 2 is "read the answer choices."
To choose the correct answer here, you only need to know that exponential growth functions are non-decreasing. The next y-values cannot be smaller than the values already shown.
_____
If you insist on doing some calculation, ...
Comparing adjacent values, you see that the common ratio is 3/2.
- 18 × 3/2 = 27
- 27 × 3/2 = 40.5
Answer: The coordinates of point B are (19 , 20).
Step-by-step explanation:
The mid point (x,y) of line joining (a,b) and (c,d) is given by :-
(1)
Given : Point A is located at (3,6). The midpoint of line segment AB is point C(11,13).
Let the coordinates of point B are (a,b) m, the according to (1) , we have
Hence, the coordinates of point B are (19 , 20).
Answer:
<h2>
WX = 3√2 units </h2>
Step-by-step explanation:
Using the formula for calculating the distance between two points to calculate the length of WX.
D = √(y₂-y₁)²+(x₂-x₁)²
Given the endpoints W(2,-7) and X(5,-4), x₁ = 2, y₁ = -7, x₂ = 5 and y₂ = -4
Substituting this values into the formula to get the length of WX will give;
WX = √(-4-(-7))²+(5-2)²
WX = √(-4+7)²+3²
WX = √3²+3²
WX = √18
WX = √2*9
WX = 3√2 units
Hence the length of WX is 3√2 units.
Answer:
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