All categories

3 years ago

Graph the function. y=-x-6 ifx<-6 y = 2x + 12 if x>-6

Mathematics

1 answer:

Naddik [55]3 years ago

7 0

Answer:

see attached

Step-by-step explanation:

For x < -6, the function has a slope of -1 and an x-intercept of -6.

For x > -6, the function has a slope of 2 and an x-intercept of -6.

The function given here is not defined at x=6, so there is a hole at (-6, 0).

You might be interested in

strip diagram shows the fractional parts of a trail dence completed. use the diagram to write a equation representing how you wo

anastassius [24]

You need to show the digarm

3 0

3 years ago

How to break down 4/5 + 13/15 = 1 2/3

nalin [4]

Answer:

Step-by-step explanation:

The left hand side of the equation contains proper fractions while the right hand side of the equation contains mixed fraction. The mixed fraction can be changed to improper fraction. 1 2/3 becomes 5/3

To breakdown the left hand side of the equation, we would take lowest common factor of 5 and 15. It is 15

Considering 4/5, if 15 divides 5,the result is 3. Multiplying 3 by 4 gives 12. So it becomes

12/15

Considering 13/15, if 15 divides 15,the result is 1, Multiplying 1 by 13 gives 13. So it becomes

13/15

The equation becomes

(12 + 13)/15 = 5/3

25/15 = 5/3

Simplifying 25/15 to its lowest terms, it becomes 5/3 so

5/3 = 5/3

6 0

3 years ago

Read 2 more answers

!!!BRAINY AND 10 PTS!!!

Dovator [93]

Answer:

its the 2nd on on the top row

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Answer the following questions about the function whose derivative is f primef′(x)equals=x Superscript negative three fifths Ba

Elden [556K]

Answer:

(a) The critical points of f are x=0 and x=3.

(b)f is decreasing on $(0,3)$ and f is decreasing on $(3,\infty)$ .

(c) Therefore the local minimum of f is at x=3

Step-by-step explanation:

Given function is

$f'(x)= x^{-\frac35}(x-3)$

(a)

To find the critical point set f'(x)=0

$\therefore x^{-\frac35}(x-3)=0$

$\Rightarrow x=0,3$

The critical points of f are 0,3.

(b)

The interval are $(0,3)$ and $(3,\infty)$ .

To find the increasing or decreasing, taking two points one point from the interval (0,3) and another point $(3,\infty)$ .

Assume 1 and 4.

Now $f'(1)=(1)^{-\frac35}(1-3)$

and $f'(4)=(4)^{-\frac35}(4-3)>0$

Since 1∈ $(0,3)$ , f'(x)<0 and 4∈ $(3,\infty)$ , f'(x)>0

∴f is decreasing on $(0,3)$ and f is decreasing on $(3,\infty)$ .

(c)

$f'(x)= x^{-\frac35}(x-3)$

Differentiating with respect to x

$f''(x)=-\frac35x^{-\frac 85}(x-3)+x^{-\frac35}$

Now

$f''(0)=-\frac35(0)^{-\frac 85}(0-3)+(0)^{-\frac35}=0$

and

$f''(3)=-\frac35(3)^{-\frac 85}(3-3)+3^{-\frac35}$

$=0.517>0$

Since f''(x)>0 at x=3

Therefore the local minimum of f is at x=3

8 0

3 years ago

Complete the equation.<br> 20 x 25 x<br> X 2

Nookie1986 [14]

Answer:

1000 is correct answer.

Step-by-step explanation:

Mark it as brainlist answer.

7 0

2 years ago