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3 years ago

Graph the function. y=-x-6 ifx<-6 y = 2x + 12 if x>-6

Mathematics

1 answer:

Naddik [55]3 years ago

7 0

Answer:

see attached

Step-by-step explanation:

For x < -6, the function has a slope of -1 and an x-intercept of -6.

For x > -6, the function has a slope of 2 and an x-intercept of -6.

The function given here is not defined at x=6, so there is a hole at (-6, 0).

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A man bought a cow and a horse for $500. He sold the cow at a profit of 10% and the horse at a loss of 10% and suffered a loss o

ycow [4]

Answer:

Step-by-step explanation:

<u>System of Equations</u>

Let's call:

x = price of the cow

y = price of the horse

The man bought the cow and the horse for $500, thus

x + y = 500 [1]

The cow was sold at a profit of 10%, thus:

Sale price of the cow= 1.1x

The horse was sold at a loss of 10%, thus:

Sale price of the horse= 0.9y

The total operation was a 2% loss, i.e. 0.98*500=490. Thus, we have:

1.1x + 0.9y = 490 [2]

From [1]:

y = 500 - x

Substituting in [2]:

1.1x + 0.9(500 - x) = 490

Operating:

1.1x + 450 - 0.9x = 490

0.2x = 490 - 450 = 40

x = 40/0.2

x = 200

The man paid $200 for the cow

3 0

2 years ago

Twenty percent of drivers driving between 10 pm and 3 am are drunken drivers. In a random sample of 12 drivers driving between 1

Lesechka [4]

Answer:

(a) 0.28347

(b) 0.36909

(d) 0.9806

Step-by-step explanation:

Given information:

n=12

p = 20% = 0.2

q = 1-p = 1-0.2 = 0.8

Binomial formula:

$P(x=r)=^nC_rp^rq^{n-r}$

(a) Exactly two will be drunken drivers.

$P(x=2)=^{12}C_{2}(0.2)^{2}(0.8)^{12-2}$

$P(x=2)=66(0.2)^{2}(0.8)^{10}$

$P(x=2)=\approx 0.28347$

Therefore, the probability that exactly two will be drunken drivers is 0.28347.

(b)Three or four will be drunken drivers.

$P(x=3\text{ or }x=4)=P(x=3)\cup P(x=4)$

$P(x=3\text{ or }x=4)=P(x=3)+P(x=4)$

Using binomial we get

$P(x=3\text{ or }x=4)=^{12}C_{3}(0.2)^{3}(0.8)^{12-3}+^{12}C_{4}(0.2)^{4}(0.8)^{12-4}$

$P(x=3\text{ or }x=4)=0.236223+0.132876$

$P(x=3\text{ or }x=4)\approx 0.369099$

Therefore, the probability that three or four will be drunken drivers is 0.3691.

(c)

At least 7 will be drunken drivers.

$P(x\geq 7)=1-P(x$

$P(x\leq 7)=1-[P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)+P(x=6)]$

$P(x\leq 7)=1-[0.06872+0.20616+0.28347+0.23622+0.13288+0.05315+0.0155]$

$P(x\leq 7)=1-[0.9961]$

$P(x\leq 7)=0.0039$

Therefore, the probability of at least 7 will be drunken drivers is 0.0039.

(d) At most 5 will be drunken drivers.

$P(x\leq 5)=P(x=0)+P(x=1)+P(x=2)+P(x=3)+P(x=4)+P(x=5)$

$P(x\leq 5)=0.06872+0.20616+0.28347+0.23622+0.13288+0.05315$

$P(x\leq 5)=0.9806$

Therefore, the probability of at most 5 will be drunken drivers is 0.9806.

5 0

3 years ago

Doug entered a conoe race he rowed 3.5 miles in .5 hrs what is his average speed

vichka [17]

7 miles per hour.

if you multiply the distance and time by 2 you get 7 miles in 1 hour, or 7 mph

4 0

3 years ago

(a) Michael bought 19 pounds of sugar for $8. How many dollars did he pay per pound

Dmitrij [34]

Answer:

A = 2.37500

B = 8.5

Step-by-step explanation:

Explanation A - 19 divided by 8 is 2.37500

Explanation B - 34 divided by 4 is 8.5

6 0

2 years ago

Please help me!!! math!!!

Genrish500 [490]

I think the answer is 17

6 0

3 years ago