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olganol [36]
2 years ago
9

Which equation represents the function graphed on the

Mathematics
1 answer:
Pavel [41]2 years ago
8 0

Answer:

A

Step-by-step explanation:

sorry im late

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Quantity of 42.1% of 375.4
Stells [14]
That is =
(42.1/100)*37.5
=(421/1000)*(375/10)
=(157875/10000)
=15.7875
=15.8
=16
8 0
3 years ago
I need help rn please​
nirvana33 [79]

Hello!

\large\boxed{\text{ slope = -3}}

Use the slope formula to solve for the slope of the line (m):

m = \frac{y^{2} -y^{1} }{x^{2} -x^{1} }

We can plug in the points (0, 4) and (1, 1) to solve:

m = \frac{1-4}{1-0}= \frac{-3}{1}  = -3

Therefore, the slope of the line is -3.

8 0
3 years ago
Choose Yes or No to tell if the fraction 5/8 will make each equation true.
uranmaximum [27]

Answer:

i need more to answer the question

Step-by-step explanation:

3 0
3 years ago
Assume that the notation (a,r,s,t) means multiply q and r, then add the product to s and (2,6,4,8)+(4,7,2,6)? Please show work a
Mama L [17]
<h3>Answer:  7.0   (choice E)</h3>

=============================================

Work Shown:

\perp (q,r,s,t) = \frac{qr + s}{t}\\\\\perp (2,6,4,8) = \frac{2*6 + 4}{8}\\\\\perp (2,6,4,8) = \frac{12 + 4}{8}\\\\\perp (2,6,4,8) = \frac{16}{8}\\\\\perp (2,6,4,8) = 2\\\\

Let m = 2 so we can use this result later.

\perp (q,r,s,t) = \frac{qr + s}{t}\\\\\perp (4,7,2,6) = \frac{4*7 + 2}{6}\\\\\perp (4,7,2,6) = \frac{28 + 2}{6}\\\\\perp (4,7,2,6) = \frac{30}{6}\\\\\perp (4,7,2,6) = 5\\\\

Let n = 5 so we can use this result later.

Add the two results.

m+n = 2 + 5 = 7.0 is the final answer.

5 0
2 years ago
(10.02)
melisa1 [442]

Answer:

sin O=\dfrac{3\sqrt{13}}{13}\\cos O=\dfrac{2\sqrt{13}}{13}\\tan O=\dfrac{3}{2}

Step-by-step explanation:

If the point (2,3) is on the terminal side of an angle in standard position.

Adjacent of O, x=2,

Opposite of O, y=3

Next, we determine the hypotenuse, r using Pythagoras Theorem.

Hypotenuse =\sqrt{Opposite^2+Adjacent^2} \\r=\sqrt{3^2+2^2} \\r=\sqrt{13}

Therefore:

sin O=\dfrac{Opposite}{Hypotenuse} \\sin O=\dfrac{3}{\sqrt{13}} \\$Rationalizing\\sin O=\dfrac{3\sqrt{13}}{13}

cos O=\dfrac{Adjacent}{Hypotenuse} \\cos O=\dfrac{2}{\sqrt{13}} \\$Rationalizing\\cos O=\dfrac{2\sqrt{13}}{13}

Tan O=\dfrac{Opposite}{Adjacent} \\tan O=\dfrac{3}{2}

4 0
3 years ago
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