All categories

3 years ago

Whats this question im confused 9/250

Mathematics

1 answer:

romanna [79]3 years ago

8 0

Its probably a division question. 250 divided by nine which is 27.7 which rounds to 28.

You might be interested in

What is the Value of C?

Kay [80]

Answer:

i d k

Step-by-step explanation:

4 0

3 years ago

(-11)-8+(-7)-(-14) Answer

goldenfox [79]

(-19) -7 +14= -26+ 14 = -12

8 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B4%20%7D%20%20%2B%205%20%3D%207" id="TexFormula1" title=" \frac{x}{4 } + 5

harina [27]

x=8 is the correct answer. First you had to subtract by 5 from both sides of equation, and it gave us, $\frac{x}{4}+5-5=7-5$ . And then simplify, and it gave us, $\frac{x}{4}=2$ . Then you can multiply by 4 from both sides of equation, and it gave us, $\frac{4x}{4}=2*4$ . And finally simplify, and it gave us the answer is 2*4=8, or x=8 is the correct answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

8 0

3 years ago

Read 2 more answers

The point P(1,1/2) lies on the curve y=x/(1+x). (a) If Q is the point (x,x/(1+x)), find the slope of the secant line PQ correct

lukranit [14]

Answer:

See explanation

Step-by-step explanation:

You are given the equation of the curve

$y=\dfrac{x}{1+x}$

Point $P\left(1,\dfrac{1}{2}\right)$ lies on the curve.

Point $Q\left(x,\dfrac{x}{1+x}\right)$ is an arbitrary point on the curve.

The slope of the secant line PQ is

$\dfrac{y_2-y_1}{x_2-x_1}=\dfrac{\frac{x}{1+x}-\frac{1}{2}}{x-1}=\dfrac{\frac{2x-(1+x)}{2(x+1)}}{x-1}=\dfrac{\frac{2x-1-x}{2(x+1)}}{x-1}=\\ \\=\dfrac{\frac{x-1}{2(x+1)}}{x-1}=\dfrac{x-1}{2(x+1)}\cdot \dfrac{1}{x-1}=\dfrac{1}{2(x+1)}\ [\text{When}\ x\neq 1]$

1. If x=0.5, then the slope is

$\dfrac{1}{2(0.5+1)}=\dfrac{1}{3}\approx 0.3333$

2. If x=0.9, then the slope is

$\dfrac{1}{2(0.9+1)}=\dfrac{1}{3.8}\approx 0.2632$

3. If x=0.99, then the slope is

$\dfrac{1}{2(0.99+1)}=\dfrac{1}{3.98}\approx 0.2513$

4. If x=0.999, then the slope is

$\dfrac{1}{2(0.999+1)}=\dfrac{1}{3.998}\approx 0.2501$

5. If x=1.5, then the slope is

$\dfrac{1}{2(1.5+1)}=\dfrac{1}{5}\approx 0.2$

6. If x=1.1, then the slope is

$\dfrac{1}{2(1.1+1)}=\dfrac{1}{4.2}\approx 0.2381$

7. If x=1.01, then the slope is

$\dfrac{1}{2(1.01+1)}=\dfrac{1}{4.02}\approx 0.2488$

8. If x=1.001, then the slope is

$\dfrac{1}{2(1.001+1)}=\dfrac{1}{4.002}\approx 0.2499$

7 0

3 years ago

Enter a recursive rule for the geometric sequence 4, -16, 64, -256 a1=_____ ; an=____

Savatey [412]

Answer:

a1 = 4 , an = - $a_{n-1} *4$

Step-by-step explanation:

The first term is already given to us and a common ration between the terms is 4 and it is oscillating between positive and negative values so it must be mulitplied by a negative.

5 0

3 years ago