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Ann [662]
3 years ago
12

Find the median of the following data set: 95, 92, 96, 93, 94, 95, 93 *

Mathematics
2 answers:
Marat540 [252]3 years ago
5 0

Answer:

93            

the median is the middle of the data set

Step-by-step explanation:

Flauer [41]3 years ago
5 0

Answer:

94.

Step-by-step explanation:

First, line the numbers up in order from least to greatest.

92, 93, 93, 94, 95, 95, 96.

Next, find the middlemost number.

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2/3 is about .66 so do .66 divided by 9 and you get .073
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Mary is doing research on bird migration. Last week she counted 12 migration birds in her yard. This week she counted 10. What w
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FRQ 1
Reptile [31]

Answer:

a) The number of visits between the patrons who buys the season passes shows higher frequency than those who did not buy season passes, in general. However, the minimum value of 1 visit is present for both cases.

b) The mean visits of the patrons are just PARAMETERS. If you want to test your hypothesis using hypothesis testing, the statistics are the z or t scores comparing the parameters (means).

c) The proportion who would have paid less are those with 2 or fewer visits because they would only just paid $82 instead of $100.

Number of patrons with 2 or fewer visits: 16

Total number of patrons who bought season passes: 30

Proportion who would've paid less = 16/30 = 0.5333

Step-by-step explanation:

I just did it

5 0
3 years ago
What is the measure of VKW?
MrRissso [65]

Answer:

107

Step-by-step explanation:

5x + 3 + 7x + 9 = 180

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6 0
3 years ago
The distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 26
hjlf

Answer:

Probability that next week's show will have between 30 and 37 million viewers is 0.2248.

Step-by-step explanation:

We are given that the distribution of the number of viewers for the American Idol television show follows a normal distribution with a mean of 26 million with a standard deviation of 8 million.

<em>Let X = number of viewers for the American Idol television show</em>

So, X ~ N(\mu=26,\sigma^{2}=8^{2})

Now, the z score probability distribution is given by;

          Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean = 26 million

            \sigma = standard deviation = 8 million

So, probability that next week's show will have between 30 and 37 million viewers is given by = P(30 < X < 37) = P(X < 37) - P(X \leq 30)

    P(X < 37) = P( \frac{X-\mu}{\sigma} < \frac{37-26}{8} ) = P(Z < 1.38) = 0.91621

    P(X \leq 30) = P( \frac{X-\mu}{\sigma} \leq \frac{30-26}{8} ) = P(Z \leq 0.50) = 0.69146

<em>Therefore, P(30 < X < 37) = 0.91621 - 0.69146 = 0.2248</em>

Hence, probability that next week's show will have between 30 and 37 million viewers is 0.2248.

4 0
3 years ago
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