Answer:
East and west side= 5 foot
South and north side = 10 foot
Area = 50 foot^2
Step-by-step explanation:
We know that:
East and west fencing cost= $4 per foot
South and north fencing cost $2 per foot
So, we can consider:
x= south and north fencing
y= east and west fencing
Then we create an equation representing the case:
Total cost = (south+north)*$2 + (east+west)*$4
80 =(x+x)*2 + (y+y)*4
80 =(2x)*2 + (2y)*4
80 =4x + 8y
80 =4*(x+2y)
80/4 =x+2y
20 = x+2y
x= 20-2y
We can calculate the area as width * length:
Area = length * width
Area= x * y
Area= (20 - 2y) * y
area= 20y - 2y^2
Next step is to find the "y" value for the maximum area so you can derivate and equal to 0 to find maximums:
d(20y - 2y^2)/dy = 20 - 2*2y = 20 - 4y
20 - 4y = 0
20 = 4y
y = 20/4
y = 5
If y = 5, then:
x = 20 - 2y
x = 20 - 2*5
x = 20 - 10
x = 10
10 seconds! you put in 0 for h, and then set the parentheses to equal zero. it can’t be negative, so it must be 10.
Answer:
Step-by-step explanation:
y=2x+4
slope=2
y- intercept=4
so draw a line through (0,2) and (2,8)
If you are solving for x.
y=2.5x+5
you subtract 5 from both sides.
-5=2.5x
then divide both sides with 2.5
-5/2.5 2.5/2.5
the 2.5s will cancel each other out.
x=-2
Answer:
<h2>The vessel in distress is located in between vessels A and B</h2>
Step-by-step explanation:
To describe how we arrive at the answer, we are going to use the drawing i have attached to this response.
southwest of ship A is just a distance around the third quadrant (using the cardinal point) and it is below A
North of B is few distances ahead of ship B.
<em>Please see the attached sketch </em>