16x + 40y.....GCF is 8
8(2x + 5y) <==
1 . Consider lineups without x. You have to select
- 2 guards from 5 quards;
- 2 forwards from 3 forwards;
- 1 center from 4 centers.
It can be made in
different ways.
2. Consider lineups with x as guard. You have to select
- 2 guards from 6 quards (one of them must be x);
- 2 forwards from 3 forwards;
- 1 center from 4 centers.
It can be made in
different ways.
3. Consider lineups with x as forward. You have to select
- 2 guards from 5 quards;
- 2 forwards from 4 forwards (one of them must be x);
- 1 center from 4 centers.
It can be made in
different ways.
Therefore, the total number of different lineups is
120+60+120=300.
83 and 89 are prime numbers between 80 and 90.
Answer:
could be better, u?
Step-by-step explanation:
Answer:
<em>H </em>= 42
Step-by-step explanation:
18 ÷ 108 = 
7 ÷
= 42
You can check to make sure your answer is right by entering your proportions into a calculator. For example,
and
also equals
so since they match, we know it is correct.
Make sure you know how to do your proportions without Brainly, that way you don't flunk your next quiz/test!