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Greeley [361]
3 years ago
5

A normal distribution has mean μ and standard deviation σ. An x-value is randomly selected from the distribution. Find P (μ − 3σ

≤ x ≤ μ)
Mathematics
1 answer:
VARVARA [1.3K]3 years ago
6 0

Answer:

49.85%

Step-by-step explanation:

P(μ − 3σ ≤ x ≤ μ)

= ½ P(μ − 3σ ≤ x ≤ μ + 3σ)

= ½ (99.7%)

= 49.85%

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