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3 years ago

Wolf brothers help me out, please no link

Mathematics

2 answers:

soldi70 [24.7K]3 years ago

6 0

Answer:

21 cards left to be signed

Step-by-step explanation:

1/3 of 72 is 24

So Harrison signed 24

3/8 of 72 is 27

Sp Alwine signed 27

24+27=51

So 72-51=21

21 cards left to be signed

Rudik [331]3 years ago

6 0

Answer:

21 cards left

Step-by-step explanation:

We know that:

72 - (Harrison + Alwine) = Cards left to sign
Harison = 1/3 x 72
Alwine = 3/8 x 72

Solution:

72 - {(1/3 x 72) + (3/8 x 72)} = Cards left to sign
=> 72 - {24 + 27} = Cards left to sign
=> 72 - {51} = Cards left to sign
=> 72 - 51 = Cards left to sign
=> 21 cards left

Hence, 21 cards are left when Harrison signs 1/3 of the cards and Alwine signs 3/8.

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Charra [1.4K]

See the picture, please!!

7 0

3 years ago

Let f(x) = -6x + 3 and g(x) = 5x + 4. Find and state its domain. -30x2 - 9x + 12; all real numbers except x = 4 -18x2 - 39x + 20

Vera_Pavlovna [14]

Unsure of whether this is a composite function or not. It does look like you've multiplied f(x) and g(x) together.

Looking at -30x2 - 9x + 12, we see immediately that this is a polynomial function. Because of that, the domain is the set of all real numbers. The graph of this poly opens down, so the max value is at the vertex, x = -b / (2a).

Here a= -6 and b= -9, so this x-value is -(-9) / (2*(-6)), or x = 9/12, or x = 3/4.

By subst. 3/4 for x in the poly., we find that the max y value is 4.83. Thus,the rante is (-infinity, 4.83].

5 0

3 years ago

This is due in 4 hours plus i have 5 classes left please help

seropon [69]

Answer:

Onaje is correct.

Step-by-step explanation:

To start, total up how many shirts we have, and multiply them by t. Since they are the same price, we now have a total for how many shirts they bought. This proves the second and third equations that they wrote. If you take the easy way and just add them, you'll still have 25t, making Onaje's expression correct.

EDIT: Just saw you need why it's incorrect for Paula, just hold on.

So for Paula, it's simple why she is incorrect. If you look at the third equation she wrote, she's adding 25 to 2t, which is completely incorrect, and will come up with a different result than 16t + 9t.

Hope this helps.

3 0

3 years ago

A breed of cattle needs at least 10 proteins and 8 fats units per day. Feed type I provides 6 protein and 2 fat units at $4 per

Vikki [24]

Let the number of bags of feed type I to be used be x and the number of bags of feed type II to be used be y, then:

We are to minimize:

C = 4x + 3y

subject to the following constraints:

$6x+2y\geq10 \\ \\ 2x+3y\geq8 \\ \\ x\geq0,\ y\geq0$

From the graph of the 4 constraints above, the corner points are (0, 5), (1, 2), (4, 0).

Testing the objective function for the minimum corner point we have:

For (0, 5):
C = 4(0) + 3(5) = $15

For (1, 2):
C = 4(1) + 3(2) = 4 + 6 = $10

For (4, 0):
C = 4(4) + 3(0) = $16.

Therefore, the combination that yields the minimum cost is 1 bag of type I feed and 2 bags of type II feed.

7 0

3 years ago

A store has 30 boxes each box has 2 bags and each bag has 3 melons. how many melons are in the store in all?

RUDIKE [14]

You first have to find out how many bags you have in total. So you multiply the number of boxes with the number of bags. After that you get the number of bags and multiply it with the number if melons in each bag.
30×2=60bags
60×3=180melons

8 0

4 years ago