Ask question

Ask question

All categories

3 years ago

13

How do you find the median on a dot plot

1 answer:

Andrei [34K]3 years ago

7 0

On the dot plot you would find the numbers, put them in order lowest to highest and either you can take a pencil and mark them out or take your two index fingers and cross the out to see what is in the middle. If there is two numbers then you add them together and divide them then that is the median.

You might be interested in

The weighted-average method is best used for

Tresset [83]

D. Homogeneous products

8 0

3 years ago

In January 2007 the population of Canada was 32 million.

kogti [31]

Answer:

21.9%

Step-by-step explanation:

7000000/32000000=0.21875

move the decimal over two places to get percent and round the 8 up because of the 7. 21.9%

6 0

3 years ago

Please help!!!!!!!!!

Phoenix [80]

Answer:

1) 1:100

2)200 ml

3) 1:50:100

Step-by-step explanation:

Egg to milk = 3:100 or 1:100

3:100=2:x x=200

Eggs to flour to milk=

3:150:300.

Or 1:50:100

Hope this helps plz mark brainliest :D

6 0

3 years ago

A geometry class is asked to find the equation of a line that is parallel to y – 3 = −(x + 1) and passes through (4, 2). Trish s

d1i1m1o1n [39]

Its C

Both students are correct

3 0

4 years ago

Read 2 more answers

In a given region, the number of tornadoes in a one-week period is modeled by a Poisson distribution with mean 2. The numbers of

klio [65]

Answer:

0.1512 = 15.12% probability that fewer than four tornadoes occur in a three-week period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

In a given region, the number of tornadoes in a one-week period is modeled by a Poisson distribution with mean 2

Three weeks, so $\mu = 2*3 = 6$

Calculate the probability that fewer than four tornadoes occur in a three-week period.

This is:

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-6}*6^{0}}{(0)!} = 0.0025$

$P(X = 1) = \frac{e^{-6}*6^{1}}{(1)!} = 0.0149$

$P(X = 2) = \frac{e^{-6}*6^{2}}{(2)!} = 0.0446$

$P(X = 3) = \frac{e^{-6}*6^{3}}{(3)!} = 0.0892$

Then

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0025 + 0.0149 + 0.0446 + 0.0892 = 0.1512$

0.1512 = 15.12% probability that fewer than four tornadoes occur in a three-week period.

7 0

3 years ago