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3 years ago

If Don weighs 250 pounds what would be his approximate weight in Kilograms

Mathematics

2 answers:

Nadusha1986 [10]3 years ago

8 0

113.398 or 113.4 is you’re rounding up

stepan [7]3 years ago

4 0

Answer:

113.398

Step-by-step explanation:

I got this answer by dividing the mass value by 2.205

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PLEASE HELP FAST 20 POINTS! Housing prices are often reported using a median. Why is median used in this case? Would arithmetic

drek231 [11]

Step-by-step explanation:

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3 years ago

What is the greatest common factor of 30,48,and 60

VARVARA [1.3K]

The GCF of 30, 48, and 60 is 6.

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3 years ago

The Wall Street Journal reported that the age at first startup for 90% of entrepreneurs was 29 years of age or less and the age

Hitman42 [59]

Answer:

(a) $\hat p\sim N(0.90,\ 0.0212^{2}})$

(b) $\hat q\sim N(0.10,\ 0.0212^{2}})$

Step-by-step explanation:

The information provided is:

The age at first startup for 90% of entrepreneurs was 29 years of age or less.
The age at first startup for 10% of entrepreneurs was 30 years of age or more.

According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.

The mean of this sampling distribution of sample proportion is:

$\mu_{\hat p}=p$

The standard deviation of this sampling distribution of sample proportion is:

$\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}$

(a)

Let p represent the proportion of entrepreneurs whose first startup was at 29 years of age or less.

A sample of n = 200 entrepreneurs is selected.

As n = 200 > 30, according to the Central limit theorem the sampling distribution of sample proportion can be approximated by the normal distribution.

Compute the mean and standard deviation as follows:

$\mu_{\hat p}=p=0.90\\\\\sigma_{\hat p}=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.90(1-0.90)}{200}}=0.0212$

So, $\hat p\sim N(0.90,\ 0.0212^{2}})$ .

(b)

Let q represent the proportion of entrepreneurs whose first startup was at 30 years of age or more.

A sample of n = 200 entrepreneurs is selected.

As n = 200 > 30, according to the Central limit theorem the sampling distribution of sample proportion can be approximated by the normal distribution.

Compute the mean and standard deviation as follows:

$\mu_{\hat q}=q=0.10\\\\\sigma_{\hat q}=\sqrt{\frac{q(1-q)}{n}}=\sqrt{\frac{0.10(1-0.10)}{200}}=0.0212$

So, $\hat q\sim N(0.10,\ 0.0212^{2}})$ .

(c)

The standard deviation of sample proportions is also known as the standard error.

The standard deviation of p is, 0.0212.

The standard deviation of q is, 0.0212.

Thus, the standard errors of the sampling distributions in parts (a) and (b) are same.

5 0

3 years ago

Solve for x. 2x2 + x = 10

Stells [14]

Answer:

x = 2, x = -5/2

Step-by-step explanation:

2x² + x - 10 = 0

(2x + 5)(x - 2) = 0

2x + 5 = 0

2x = -5

x = -5/2

x - 2 = 0

x = 2

8 0

3 years ago

The table below shows a correct representation that 16 pounds (lb) of sugar cost 4$:

Fynjy0 [20]

This is true. If you count the number of lbs, you get 16 and if you count the number of dollars in the same length, you get $4.

8 0

3 years ago

If Don weighs 250 pounds what would be his approximate weight in Kilograms​

If Don weighs 250 pounds what would be his approximate weight in Kilograms