Answer:
4z^2+7z
you have to combine the like terms
7z+4z^2+6-6
then becomes
(4z^2) + (7z) + (6-6)
gets you to the simplified version which is
4z^2 +7z
I will suppose that your queation is 10<x<y<14
there are only two odd between 10 and 14
which are 11 and 13
since x is smaller than y
x=11 and y=13
there sum will be x+y=11+13=24
Answer:
credit line but this is more of business not a math subject btw
Positive and a positive, will always be a positive because theyre both the same. If two things are the same, theyre equal. ( this is from what ik,I read it as a common sense question)
