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3 years ago

Which ordered pair is a solution to the system of linear equations?

2 answers:

4 0

Step 1: Substitute the value of x into the equation
x= 3-3/2y
-3x+5y=10

Step 2: Solve the equation
-3(3-3/2y)+5y=10

Step 3: Substitute the value of y into the equation
Y=2

Step 4: Solve the equation
X=3-3/2×2 = X=0

Answer: (0,2)

Mars2501 [29]3 years ago

3 0

Answer:

Step 1: Substitute the value of x into the equation

x= 3-3/2y

-3x+5y=10

Step 2: Solve the equation

-3(3-3/2y)+5y=10

Step 3: Substitute the value of y into the equation

Y=2

Step 4: Solve the equation

X=3-3/2×2 = X=0

Answer: (0,2)

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Can someone help me solve this?!

vesna_86 [32]

Answer:

10x+2

Step-by-step explanation:

First we work on the paranthesis. We will times 5 and 2x to get 10x

and then we times 5 and 3/4 to get 3 $\frac{3}{4}$

So now we have 10x+3 $\frac{3}{4}$ -1.75

Next, we subtract 3 $\frac{3}{4}$ -1.75 which is 2

Lastly we look at the equation as a whole!

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3 years ago

What us the midpoint of A(-8,2) and B(4,-2)

marusya05 [52]

Answer:

(-2 , 2)

Step-by-step explanation:

A(-8 , 2) = (x1 , y1)

B(4 , -2) = (x2 , y2)

midpoint = (x1 + x2/2 , y1 + y2/2)

=(-8 + 4/2 , 2-(-2)/2)

=(-4/2 , 2+2/2)

(-2 , 2)

(3 , 7) = (x1 , y1)

(9 , 2) = (x2 , y2)

distance of PQ = $\sqrt{(x2 - x1)^2 + (y2 - y1)^2}$

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= $\sqrt{(6)^2 + (-5)^2}$

= $\sqrt{36 + 25}$

= $\sqrt{61}$

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2 years ago

Consider a population with data values of 12, 8, 28, 22, 12, 30, 14. the median is:

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First we put the numbers in order...
8,12,12,14,22,28,30

the median (middle number) is 14 <==

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3 years ago