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3 years ago

Question 7 Which set of side lengths can be used to form a right triangle?

Mathematics

1 answer:

olga2289 [7]3 years ago

6 0

Answer:

D.30,40,50

Step-by-step explanation:

A.4,5,6

B.2,3,4

C.10,20,30

D.30,40,50

The Pythagoras theorem : a² + b² = c²

where a = length

b = base

c = hypotenuse

4² + 5² = 25 is not equal to the square of 6 which is 36

2² + 3² = 10 . 10 is not equal to the square of 4 which is 16

10² + 20³ = 500. 500 is not equal to the square of 30 which is 900

30² + 40² = 2500. this is equal to the square of 50

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Pls pls help<br> Show work :)

Natasha2012 [34]

9514 1404 393

Answer:

31.243 units

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the relationships between sides and angles in a right triangle. Using the attached figure, it is convenient to find the length of BE as an intermediate step in the solution.

Sin = Opposite/Hypotenuse

sin(30°) = BE/100

BE = 100·sin(30°)

Then ...

Tan = Opposite/Adjacent

tan(58°) = BE/x

x = BE/tan(58°) = 100·sin(30°)/tan(58°)

x ≈ 31.243 . . . . units

_____

<em>Comment on the figure</em>

The intermediate problem in creating the figure was to locate point D. That was accomplished by locating point C on a line at an angle of 58° CCW from the horizontal, using point B as a center. Then D is the intersection of BC with the x-axis. BE is drawn perpendicular to the x-axis.

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