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3 years ago

TERE

Mathematics

1 answer:

Nonamiya [84]3 years ago

5 0

Answer: C The value of the first quartile is 13.

Step-by-step explanation:

I’m taking the test and i think i got the right i’m very sorry if it’s wrong

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If the terminal point of ø is (1,0), what is tan ø?

charle [14.2K]

Given:

The terminal point of $\phi$ is (1,0).

To find:

The value of $\tan\phi$ .

Solution:

If the terminal point of $\theta$ is (x,y), then

$\tan \theta=\dfrac{y}{x}$

It is given that the terminal point of $\phi$ is (1,0).

Here, x-coordinate is 1 and the y-coordinate is 0. Using the above formula, we get

$\tan \phi=\dfrac{0}{1}$

$\tan \phi=0$

Therefore, the value of $\tan \phi$ is 0.

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3 years ago

When I think of a number, double it, then add seven, I get 25. what number did I think of?

sweet [91]

Answer:

Step-by-step explanation:

25-7=18

half of 18 is 9

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3 years ago

Read 2 more answers

Brad says that if a second number is 125% of the first number than the second number must be 75% of the second number is he corr

elena-s [515]

Answer:

Incorrect.

Step-by-step explanation:

Let, the first number is x, and the second number is y. Given, the second number is 125% of the first number. So, the equation will be

y = 1.25 x

Or, y= 5/4x

Now, multiplying it with 4/5, we get, x= 4/5y

Or, x= 0.80 y

But, Brad is saying the first number must be 75% of the second number. But here we see that the first number is 80% of the second number. That's why Brad is incorrect.

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3 years ago

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

This implies that they go on round after $11\frac{2}{3}\ min$

4 0

3 years ago

Hi! ❤️ sending love to all I’m wishing for some super needed help here

nevsk [136]

Answer:

SEE THE IMAGE FOR ALL ANSWERS.

4 0

3 years ago