All categories

3 years ago

I need the work shown please and thank you

Mathematics

1 answer:

Crazy boy [7]3 years ago

5 0

A, C, D are the options in which the numbers are less than 4.47

Step-by-step explanation

The numbers represented here are ones which do not have proper root square numbers. These numbers are irrational.
Since they do not have proper root square values there are certain techniques to find their approximate value.
Here, we use the numbers which have proper root square values. These numbers are being expressed as the multiples of the given numbers. Then, we will find the approximate values to it. Hence, it answers to those roots

You might be interested in

Which expressions are polynomials? Select the two correct answers.

alexdok [17]

Someone help on this question I also need the answer to it

5 0

3 years ago

Please help i’ve been here for hours so can someone please tell me what to put here

andreev551 [17]

Answer:

If you divide the amount $60.20 (60.20) by 5 (amount of hours), you can find out the amount of money Andrew gets paid in dollars per hour. The quotient is 12.04, $12.04. Therefore, Andrew is payed $12.04 per hour.

Step-by-step explanation:

HOPE THIS HELPS

HAVE A GOOD DAY

STAY SAFE BYEE

❤

6 0

4 years ago

Read 2 more answers

If 2+2 is 4 than what is 10+10

Leto [7]

Answer:

Step-by-step explanation:

10 +10=20

8 0

3 years ago

Read 2 more answers

Can you help me with my work don’t send no link

vazorg [7]

B and d r correct yuh yuh

3 0

3 years ago

Read 2 more answers

23 degrees 20’48 is the same as _degrees.

allochka39001 [22]

Answer:

$\large\boxed{23^o20'48''=\left(23\dfrac{26}{75}\right)^o}$

Step-by-step explanation:

$\text{We know:}\\\\1^o=60'\to1'=\left(\dfrac{1}{60}\right)^o\\\\1'=60''\to1^o=(60)(60'')=3600''\to1''=\left(\dfrac{1}{3600}\right)^o\\\\23^o20'48''\\\\20'=\left(\dfrac{20}{60}\right)^o=\left(\dfrac{1}{3}\right)^o\\\\48''=\left(\dfrac{48}{3600}\right)^o=\left(\dfrac{1}{75}\right)^o\\\\\text{Therefore}\\\\23^o20'48''=23^o+20'+48''=23^o+\left(\dfrac{1}{3}\right)^o+\left(\dfrac{1}{75}\right)^o\\\\=\left(23+\dfrac{1\cdot25}{3\cdot75}+\dfrac{1}{75}\right)^o=\left(23+\dfrac{25}{75}+\dfrac{1}{75}\right)^o=\left(23\dfrac{26}{75}\right)^o$

4 0

4 years ago