Area of a square:
A= side^2
= (6x + 1) ^2
=<u> 36x^2 + 12x + 1 feet^2</u>
M=(6-1)/(8-5)=5/3
y=5x/3+b, using (5,1)
1=25/3+b
b=-22/3
y=(5x-22)/3
...
m=(8-3)/(-1--4)=5/3...
y=5x/3+b, using (-1,8)
8=-5/3+b
b=29/3
y=(5x+29)/3
Since they have the same slope and difference y-intercepts they are parallel lines and will never intersect.
Answer:
A. Adding the values of the intercepted arcs and that is equal to twice the angle measure
Step-by-step explanation:
The intersecting chords theorem states that when four line segments are formed by two chords intersecting in a circle, the product of the two line segments on one chord is equal to the product of the two line segments on the other chord
The angles of intersecting chords theorem states that the angles formed by the intersecting chords one half the sum of the arcs intercepted by the chords
In the diagram attached, we have;
∠x = ∠y + ∠z
m
= 2·∠z, m
= 2·∠y
∴ ∠x = (1/2) × m
+ m
m
+ m
= 2 × ∠x
The correct option is therefore adding the values of the intercepted arcs and that is equal to twice the angle measure.
Answer:
x=-6
Y=4
Step-by-step explanation:
Answer:
Step-by-step explanation:
The max and min values exist where the derivative of the function is equal to 0. So we find the derivative:

Setting this equal to 0 and solving for x gives you the 2 values
x = .352 and -3.464
Now we need to find where the function is increasing and decreasing. I teach ,my students to make a table. The interval "starts" at negative infinity and goes up to positive infinity. So the intervals are
-∞ < x < -3.464 -3.464 < x < .352 .352 < x < ∞
Now choose any value within the interval and evaluate the derivative at that value. I chose -5 for the first test number, 0 for the second, and 1 for the third. Evaluating the derivative at -5 gives you a positive number, so the function is increasing from negative infinity to -3.464. Evaluating the derivative at 0 gives you a negative number, so the function is decreasing from -3.464 to .352. Evaluating the derivative at 1 gives you a positive number, so the function is increasing from .352 to positive infinity. That means that there is a min at the x value of .352. I guess we could round that to the tenths place and use .4 as our x value. Plug .4 into the function to get the y value at the min point.
f(.4) = -48.0
So the relative min of the function is located at (.4, -48.0)