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3 years ago

Can someone please help me with the question, a/4 = 15/12 a=?

Mathematics

2 answers:

malfutka [58]3 years ago

7 0

Answer:

a = 5

Step-by-step explanation:

a/4 = 15/12

We can use cross products to solve

a* 12 = 4*15

12a = 60

Divide each side by 12

12a/12 = 60/12

a =5

Bumek [7]3 years ago

4 0

Answer:

a = 5

Step-by-step explanation:

a/4 = 15/12

Cross Multiplying RHS to LHS, we get

12a = 60

a = 60/12

a = 5

hope it helps!

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(-18x^2+12x-2)*(x^3+12x^2+48x+64)

prohojiy [21]

<h2>Answer:</h2>

-18x^5-204x^4-722x^3-600x^2+672x-128

<h2>Explanation:</h2>

$( - 18 {x}^{2} + 12x - 2)$

$( {x}^{3} + 12 {x}^{2} + 48x + 64)$

There are multiple ways to solve this for example the foil method or the box method. I prefer to do the box method.

First we are going to set it up

After we set it up we have to solve it so first we are going to multiply

${x}^{3} \times - 18 {x}^{2} = - 18 {x}^{5}$

We have to add the exponent

$- 18 {x}^{2} \times 12 {x}^{2} = - 216 {x}^{4}$

$- 18 {x}^{2} \times 48x = - 864 {x}^{3 } \\ - 18{x}^{2} \times 64 = - 1152 {x}^{2} \\ 12x \times {x}^{3} = 12 {x}^{4} \\ 12x \times 12 {x}^{2} = 144 {x}^{3}$

$12x \times 48x = 576 {x}^{2} \\ 12x \times 64 = 768x$

$- 2 \times {x}^{3} = - 2 {x}^{3} \\ - 2 \times 12 {x}^{2} = - 24 {x}^{2} \\ - 2 \times 48x = - 96x \\ - 2 \times 64 = - 128$

Now we have to add them

-18x^5 stays because there is nothing to add to

Now we add the rest

$-216 {x}^{4} + 12 {x}^{4} = - 204 {x}^{4}$

$- 864 {x}^{3} + 144 {x}^{3} + - 2 {x}^{3} = - 722 {x}^{3}$

$768x - 96x = 672x$

And -128 stays the same

$- 1152 {x}^{2} + 576 {x}^{2} - 24 {x}^{2} = - 600 {x}^{2}$

The answer is

-18x^5-204x^4-722x^3-600x^2+672x-128

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4 years ago

Help...1. Simplify 2+17x-5x+9......

Ira Lisetskai [31]

2 + 17x - 5x + 9

First, subtract 17x - 5x to get 12x.
$2 + 12x + 9$
Second, leave the 12x be and add 2 + 9 to get 11.
$12x + 11$

Answer: 12x + 11

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3 years ago