Question

Here is a better picture!​

Answer 1

Answer:

Part A:  A) $\frac{4y^{10}}{3w}$

Part B:

C) Quotient Rule of Powers (explained in Part A of this post).

D) Zero Exponent Rule (explained in Part A of this post, in solving for base z).

Step-by-step explanation:

$\frac{28y^{15}w^{3} z^{7}}{21y^{5}w^{4} z^{7}}$

Part A:

Use the Quotient Rule of Exponents:

$\frac{a^{m}}{a^{n}} = a^{m-n}$

The 28 and 21 can be reduced by dividing both of them by 7.  For the exponential expressions with the same base, you could subtract their exponents.  I'll do each base separately so it doesn't get confusing.

$\frac{28y^{15}w^{3} z^{7}}{21y^{5}w^{4} z^{7}}$

Base y:

$y^{15-5}$ = $y^{10}$ (in the numerator).

Base w:

$w^{4-3}$ = w (in the denominator. The "w" in the numerator cancels out).

Base z:

$z^{7-7}$ = $z^{0} = 1$  We used the Zero Exponent Rule here, were it states: $a^{0} = 1$. (unnecessary to include in the final answer).

Altogether, you'll have:

Option A: $\frac{4y^{10}}{3w}$

Part B:

C) Quotient Rule of Powers (explained in Part A of this post).

D) Zero Exponent Rule (explained in Part A of this post, in solving for base z).