Answer:
<em>Thus, the transformation from ABC to A'B'C' is a reflection over the x-axis.</em>
<em>Choice 1.</em>
Step-by-step explanation:
<u>Reflection over the x-axis</u>
Given a point A(x,y), a reflection over the x-axis maps A to the point A' with coordinates A'(x,-y).
The figure shows triangles ABC and A'B'C'. It can be clearly seen the x-coordinates for each vertex of both triangles is the same and the y-coordinate is the inverse of it counterpart. For example A=(5,3) and A'=(5,-3)
Thus, the transformation from ABC to A'B'C' is a reflection over the x-axis.
Choice 1.
For 6 I think it was B I am not so sure. Its been a long time since i did triangles
If each linear dimension is scaled by a factor of 10, then the area is scaled by a factor of 100. This is because 10^2 = 10*10 = 100. Consider a 3x3 square with area of 9. If we scaled the square by a linear factor of 10 then it's now a 30x30 square with area 900. The ratio of those two areas is 900/9 = 100. This example shows how the area is 100 times larger.
Going back to the problem at hand, we have the initial surface area of 16 square inches. The box is scaled up so that each dimension is 10 times larger, so the new surface area is 100 times what it used to be
New surface area = 100*(old surface area)
new surface area = 100*16
new surface area = 1600
Final Answer: 1600 square inches
We know that
The square root property<span> is one method that is used to find the solutions to a quadratic equation. This method involves taking the square roots of both sides of the equation.
</span>(x – 3)² – 32 = 17-------> (x – 3)² = 17+32-----------> (x – 3)² = 49
(x – 3)² = 7²--------> <span>will take the square root of each side
</span>so
√(x – 3)²=(+-)√7²------> <span>notice the use of the </span> sign (+-), this will give us both a positive and<span> a negative root
</span>
then
x-3=7--------> x=10
x-3=-7-------> x=-4
the answer Part a) is
x=10
x=-4
Part b) Explain why the given equation has two solutions.
the answer part b) is
Because exist<span> the possibility of two roots for every square root, one positive and one negative</span>
Answer:
where's the problem
Step-by-step explanation:
