All categories

3 years ago

Given cosx=12/13

1 answer:

7 0

1. You have the following information:

Sinx=5/13

Cosx=12/13

2. By definiton, you have:

Tanx=(Senx)/(Cosx)

3. When you susbtitute Senx=5/13 and Cosx=12/13 into Tanx=(Senx)/(Cosx), you obtain:

Tanx=(Senx)/(Cosx)
Tanx=(5/13)/(12/13)
Tanx=(5)(13)/(13)(12)
Tanx=65/156

4. Therefore, the answer is;

Tanx=65/156

You might be interested in

3.1 = x / 2 equals what?

neonofarm [45]

Answer: 6.2

Step-by-step explanation: 3.1 = x/2

x/2=3.1

x/2(2)=3.1(2)

x=6.2

3 0

3 years ago

Today i will walk 3 miles per hour to school, which is 1.5 miles away how many hours would this trip take

GaryK [48]

Answer: 30 minutes so 1/2 hour

Step-by-step explanation:

Because 3 miles = 1 hour

1.5 times 2 = 3

divide 2 on both sides

4 0

3 years ago

Read 2 more answers

A circular patio has a diameter of 12 feet. Holly is stringing lights around the edge of the patio. Approximately how many feet

vivado [14]

Answer:

37.68

i took the test hope this helped

4 0

2 years ago

Find the sum of 3.8 + (-2.9)

MakcuM [25]

Answer:

3.8 - 2.9= .9

ANSWER : .9

6 0

2 years ago

Read 2 more answers

Water flows into a tank according to the rate F of t equals the quotient of 6 plus t and the quantity 1 plus t, and at the same

diamong [38]

Answer:

Step-by-step explanation:

The complete question is

Water flows into a tank according to the rate F(t)= (t+6)/(1+t), and at the same time empties out at the rate E(t)= (ln(t+2))/(t+1), with both F(t) and E(t) measured in gallons per minute. How much water, to the nearest galllon, is in the tank at time t=10 minutes.

Let C(t) be the amount of water in the tank at time t. We now that the rate of change of the tank is given by

$\frac{dC}{dt}=[\tex]rate at which water flows in- rate at which water flows out. Then [tex]\frac{dC}{dt}=\frac{t+6}{t+1}-\frac{\ln(t+2)}{(t+1)}[\tex]so, the desired expression is obtained by integrating with respect to t. This leads us to [tex]C(t) = \int \frac{t+1}{t+1}+ \frac{5}{t+1} - \frac{\ln(t+2)}{(t+1)} dt=t+ 5 \ln (|t+1|)-\int \frac{\ln(t+2)}{(t+1)} dt +C$

Unfortunately, the integral $\int \frac{\ln(t+2)}{(t+1)} dt$ cannot be expressed using fundamental functions. So, the problem cannot have an specific function (if you are willing to know the complete answer, the integral of this function uses the polylogarithm function with n=2).

Since you want the exact amount of water at time, you need to give C a value, that is, you need to know an initial condition for the problem. This means, you need to know the amount of water in the tank at time 0

8 0

3 years ago