15/16 as a fraction or 3.125 as a decimal
Answer:
12x2+2x6x34÷1613÷14
Step-by-step explanation:
I think its about 62 hours because you multiply the 185 days by 20 minutes and get 3,700 so you divide that by 60 and get 61.6666667. so the answer is 62 hours?
It doubles every 4 hours, so after 24 hours there will be 6 doublings.
2^6 = 64
So, the population will be (3,000,000 * 64) or 192,000,000 in 24 hours.
The answer is B.
Answer:
The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the z-score that has a p-value of
.
427 had paid for coaching courses and the remaining 2733 had not.
This means that ![n = 427 + 2733 = 3160, \pi = \frac{427}{3160} = 0.1351](https://tex.z-dn.net/?f=n%20%3D%20427%20%2B%202733%20%3D%203160%2C%20%5Cpi%20%3D%20%5Cfrac%7B427%7D%7B3160%7D%20%3D%200.1351)
95% confidence level
So
, z is the value of Z that has a p-value of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 - 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.1232](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.1351%20-%201.96%5Csqrt%7B%5Cfrac%7B0.1351%2A0.8649%7D%7B3160%7D%7D%20%3D%200.1232)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.1351 + 1.96\sqrt{\frac{0.1351*0.8649}{3160}} = 0.147](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.1351%20%2B%201.96%5Csqrt%7B%5Cfrac%7B0.1351%2A0.8649%7D%7B3160%7D%7D%20%3D%200.147)
The 95% confidence interval for the proportion of students who get coaching on the SAT is (0.1232, 0.147).