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MrRissso [65]
3 years ago
15

Adrian built a structure out of 10 congruent cubes. If each cube has a volume of 8 cu. centimeters, what is the total

Mathematics
1 answer:
kobusy [5.1K]3 years ago
4 0

Answer:

Option (b).

Step-by-step explanation:

It is given that Adrian built a structure out of 10 congruent cubes.  

Volume of each cube = 8 cubic centimetres.

We need to find the total volume of the structure.

Total volume = No. of cubes × Volume of each cube

V=10\times 8

V=80

Therefore, the total volume of the structure is 80 cubic centimetres.

Hence, option (b) is correct.

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A vitamin powder weighs 0.0002 pound.
hichkok12 [17]

Answer:

A. 6.2 X 10 ^-3

Step-by-step explanation:

First, you have to find the total weight by adding 0.0002 and 0.006 together, which gives you 0.0062. Then, follow basic setup of scientific notation by moving the decimal until one non-zero digit is to the left of the decimal, which brings the decimal to 6.2. Since you are moving the decimal right three places, the exponent is negative 3, making the notation 6.2 X 10 ^-3

6 0
3 years ago
The largest number that rounds to 2,500 when rounded to the nearest ten?
Savatey [412]
2504, as 2499 is 5 less, yet rounds to 2.5K. It is the highest possible for rounding to the tens, as 2505 rounds to 2510.
5 0
3 years ago
Read 2 more answers
Coach Stevens needs to purchase sprinklers to water the baseball field. The standard distance between bases is 90 feet and the i
egoroff_w [7]
If you need the geometry and trigonometry I'll post those.  Instead I found an answer at this link: http://jwilson.coe.uga.edu/EMAT6450/Class%20Projects/Scarpelli/Scarpelli_MathematicsBaseballActivity.....
The distance from home plate to the pitcher's mound is 60.5 feet and from home plate to second base is <span>127.28 feet.
Pitcher's Mound to 2nd base = </span><span> <span> <span> 66.78</span> </span>f</span>eet

Given those distances, we KNOW a 50 foot sprinkler will NOT reach home plate and second base from the pitcher's mound.

I didn't figure out the pitcher's mound to 1st or to 3rd, since the question is already answered.


6 0
3 years ago
Find the Maclaurin polynomials of orders n = 0, 1, 2, 3, and 4, and then find the nth Maclaurin polynomials for the function in
Zielflug [23.3K]

Answer:

Σ(-1)^kx^k for k = 0 to n

Step-by-step explanation:

The nth Maclaurin polynomials for f to be

Pn(x) = f(0) + f'(0)x + f''(0)x²/2! + f"'(0)x³/3! +. ......

The given function is.

f(x) = 1/(1+x)

Differentiate four times with respect to x

f(x) = 1/(1+x)

f'(x) = -1/(1+x)²

f''(x) = 2/(1+x)³

f'''(x) = -6/(1+x)⁴

f''''(x) = 24/(1+x)^5

To calculate with a coefficient of 1

f(0) = 1

f'(0) = -1

f''(0) = 2

f'''(0) = -6

f''''(0) = 24

Findinf Pn(x) for n = 0 to 4.

Po(x) = 1

P1(x) = 1 - x

P2(x) = 1 - x + x²

P3(x) = 1 - x+ x² - x³

P4(x) = 1 - x+ x² - x³+ x⁴

Hence, the nth Maclaurin polynomials is

1 - x+ x² - x³+ x⁴ +.......+(-1)^nx^n

= Σ(-1)^kx^k for k = 0 to n

6 0
3 years ago
I need answers to this
ololo11 [35]

Answer:

x = -5, and y = -6

Step-by-step explanation:

Suppose that we have two equations:

A = B

and

C = D

combining the equations means that we will do:

First we multiply both whole equations by constants:

k*(A = B) ---> k*A = k*B

j*(C = D) ----> j*C = j*D

And then we "add" them:

k*A + j*C = k*B + j*D

Now we have the equations:

-x  - y = 11

4*x - 5*y = 10

We want to add them in a given form that one of the variables cancels, so we can solve it for the other variable.

Then we can take the first equation:

-x  - y = 11

and multiply both sides by 4.

4*(-x - y = 11)

Then we get:

4*(-x - y) = 4*11

-4*x - 4*y = 44

Now we have the two equations:

-4*x - 4*y = 44

4*x - 5*y = 10

(here we can think that we multiplied the second equation by 1, then we have k = 4, and j = 1)

If we add them, we get:

(-4*x - 4*y) + (4*x - 5*y) = 10 + 44

-4*x - 4*y + 4*x - 5*y = 54

-9*y = 54

So we combined the equations and now ended with an equation that is really easy to solve for y.

y = 54/-9 = -6

Now that we know the value of y, we can simply replace it in one of the two equations to get the value of x.

-x - y = 11

-x - (-6) = 11

-x + 6 = 11

-x = 11 -6 = 5

-x = 5

x = -5

Then:

x = -5, and y = -6

5 0
3 years ago
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