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kipiarov [429]
3 years ago
5

PLEASE HELP!!! How many solutions does each polynomial have?​

Mathematics
1 answer:
kkurt [141]3 years ago
5 0
Try using M-A-T-H-W-A-Y it is very helpful
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Expand using the properties and rules for logarithms
malfutka [58]

Consider expression \log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right).

1. Use property

\log_a\dfrac{b}{c}=\log_ab-\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2.

2. Use property

\log_abc=\log_ab+\log_ac.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2.

3. Use property

\log_ab^k=k\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+\log_{\frac{1}{2}}x^2-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2.

4. Use property

\log_{a^k}b=\dfrac{1}{k}\log_ab.

Then

\log_{\frac{1}{2}}\left(\dfrac{3x^2}{2}\right)=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{\frac{1}{2}}2=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x-\log_{2^{-1}}2=\\ \\=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+\log_22=\log_{\frac{1}{2}}3+2\log_{\frac{1}{2}}x+1.

Answer: correct option is B.

7 0
3 years ago
Please help me! I have to sumbmit in 15 minutes!
kompoz [17]

Answer:

The answer is 1030 ml

Hope this helps

5 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST ASAP NEEDED PLS ANSWER HELP
Alika [10]

Answer:

$47,520

Step-by-step explanation:

A.

the area of a polygon is/

A= perimeter X apothem /2

A=500

apothem = 10

500 = (P * 10)/2

P =100

B. 100*7.95 = $795

C.

60*100= 6,000

6,000 * $7.95=

$47,520

7 0
3 years ago
40.4 Kilograms round to the nearest hundreth​
Romashka-Z-Leto [24]

Answer: 40.4 rounded to the nearest hundredth would be 40.40

Step-by-step explanation: There is no oneth in decimals so it goes from tenth, to hundredth, to thousandth. Since there is no number in the hundredth or thousandth's space, you would put a zero in both spots. zero in the thousandths is NOT greater than 5 so the zero in the hundredths space will stay as a zero, making the answer 40.40

3 0
3 years ago
Read 2 more answers
Simplify the following rational expression.
Jet001 [13]

9514 1404 393

Answer:

  (x-8)/(4x-4)  x ≠ 1 or 8

Step-by-step explanation:

Common factors can be cancelled, but cannot be ignored when it comes to determining where the function is undefined.

  \dfrac{x^2-16x+64}{4x^2-36x+32}=\dfrac{(x-8)^2}{4(x-8)(x-1)}=\boxed{\dfrac{x-8}{4x-4}}

The function is undefined for x=1 and x=8, the values of x that make the original denominator zero.

8 0
3 years ago
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