Answer:
The order must be K2→K1, since the permanently active K1 allele (K1a) is able to propagate the signal onward even when its upstream activator K2 is inactive (K2i). The reverse order would have resulted in a failure to signal (K1a→K2i), since the permanently active K1a kinase would be attempting to activate a dead K2i kinase.
Explanation:
- You characterize a double mutant cell that contains K2 with type I mutation and K1 with type II
mutation.
- You observe that the response is seen even when no extracellular signal is provided.
- In the normal pathway, i f K1 activat es K2, we expect t his combinat ion of two m utants to show no response with or without ext racell ular signal. This is because no matt er how active K1 i s, it would be unable to act ivate a mutant K2 that i s an activit y defi cient. If we reverse the order, K2 activating K1, the above observati on is valid. Therefore, in the normal signaling pathway, K2 activates K1.
Answer:
I am almost positiv it is genetic diversity
Answer:
D
a buffer is an ionic compound that resists change in ph hence no ph change on addition of an acid proves the presence of a buffer which is different when distilled water is added because it is neutral hence no increase or decrease in ph
Answer:
1. Cytokinesis represents the major reproductive procedure of unicellular organisms, and it occurs in the process of embryonic development and tissue growth and repair of higher plants and animals.
2. Cytokinesis performs an essential process to separate the cell in half and ensure that one nucleus ends up in each daughter cell. Cytokinesis starts during the nuclear division phase called anaphase and continues through telophase.
Energy can neither be created or destroyed but does however transform from one form to another
