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aalyn [17]
3 years ago
5

Find the value of u. If the volume is 560

Mathematics
1 answer:
Arada [10]3 years ago
5 0

Answer:

10 ft

Step-by-step explanation:

V = l*w*h

560 = 7*8 *u

560 = 56u

divide each side by 56

560/56 = 56u/56

10 =u

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The expression 3r - 6 can be written as _____. A:3(r - 2) B:3(r - 6) C:3(3r - 6)
Zolol [24]

Answer:

<h3>\boxed{ \bold{ \sf{ \boxed{3(r - 2)}}}}</h3>

Option A is the correct option.

Step-by-step explanation:

\sf{3r - 6}

▪️If there is a common factor in each term of an expression, the common factor can be taken as the factor with the remaining terms.

Here, taking 3 common

\sf{3(r - 2)}

Hope I helped!

Best regards!!

3 0
4 years ago
Read 2 more answers
Anita incorrectly wrote the equation z = w – 18 to describe the pattern in the table.
Alina [70]

Answer:

B C and D

Step-by-step explanation:

Mark brainliest

P.S this was epert verified

8 0
3 years ago
Read 2 more answers
What is the value for f(x)4^2x -100 when x=2 ?<br><br> (the ^2x is a exponent)
PolarNik [594]

Answer:

156

Step-by-step explanation:

f(x)= 4^(2x) -100

Let x =2

f(2)= 4^(2*2) -100

   = 4^4 - 100

   = 256 -100

   = 156

3 0
3 years ago
What's 3/6-4/6 and simply your answer
Yuri [45]
Your answer would be -1/6
8 0
3 years ago
Rosa and Albert receive the same amount of allowance each week . The table shows what part of their allowance they each spent on
Anettt [7]
1/2 x > 0.4x

where Robert's spending is greater than Rosa's spending.

Allowance of Rosa = Allowance of Robert

let x = allowance

Rosa : video games = 0.4(x) ; pizza = 2/5 (x)
Robert : video games = 1/2 (x) ; pizza = 0.25 (x)

let us assume that their allowance is 100 each week. so, x = 100

Rosa : video games = 0.40(100) = 40
           pizza 2/5 (100) = 200/5 = 40
total spending: 40 + 40 = 80

Robert : video games = 1/2 (100) = 50
             pizza 0.25 (100) = 25
total spending: 50 + 25 = 75

Spending on video games
Rosa = 40
Robert = 50

Robert spent more of his allowance on video games than Rosa.

1/2 x > 0.4x
7 0
4 years ago
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