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4 years ago

Answer these questions please

Mathematics

1 answer:

Contact [7]4 years ago

5 0

Answer:

UwU

Step-by-step explanation:

SOLO QUIERO PUNTOS

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The equation of the tangent to the curve x^2 = 4y at the point on the curve where x=-2 is?

aleksandrvk [35]

$x^2 = 4y \Rightarrow y= \frac{x^2}{4}$
$\frac{dy}{dx} = \frac{2x}{4} = \frac{x}{2}$

(x = -2) $\frac{dy}{dx} = \frac{x}{2} = \frac{-2}{2} = -1$
(x = -2) $y= \frac{x^2}{4}= \frac{(-2)^2}{4} = 1$

$y-y_1=m(x-x_1)$
$y-1 = -1(x--2)
$
$y-1 = -1(x+2)$
$y-1 = -x-2$
$y=-x-1 = -(x+1)$

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4 years ago

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Describe how to solve d = rt for t

kotegsom [21]

Answer:

t = d/r

Step-by-step explanation:

Given the equation, d = rt for <em>t</em><em>:</em>

Switch sides:

rt = d

Divide both sides by r to isolate<em> t</em>:<em> </em>

$\frac{rt}{r} = \frac{d}{r}$

t = d/r

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3 years ago

WRITE Math How are a common denominator and a common<br> multiple alike and different?

Vesnalui [34]

That are different because that are not!!!!! the same ?

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4 years ago

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Lines g, h, and l are parallel and m< 2 = 129°.

liubo4ka [24]

<12 would be A (51 degrees) because 2 and 10 are corresponding angles and there are 180 degrees on a straight line!
Hope this helps :)

5 0

3 years ago

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NO LINKS!! Please help with questions 3 and 4

Taya2010 [7]

Answer:

$\textsf{3.} \quad (x,y) \rightarrow (x-5,y+2)$

$\textsf{4.} \quad (x,y) \rightarrow (x+3,y+1)$

Step-by-step explanation:

<h3><u>Question 3</u></h3>

Given vertices of ΔLMN:

L = (1, -1)
M = (4, 1)
N = (5, -1)

Given vertices of ΔL'M'N':

L' = (-4, 1)
M' = (-1, 3)
N' = (0, 1)

From inspection of the given diagram, we can see that the two triangles are congruent since their corresponding angles and corresponding side lengths are the same.

There is no apparent reflection or rotation, so the transformation of ΔLMN to ΔL'M'N' is by translation.

To find the mapping rule for the translation, choose one pair of corresponding vertices and determine the difference between the x and y values of the translated point and the original point:

$x_{M'}-x_M =-1-4=-5 \implies \textsf{5 units left}$

$y_{M'}-y_M =3-1=2 \implies \textsf{2 units up}$

Therefore, the mapping rule for the translation is:

$(x,y) \rightarrow (x-5,y+2)$

<h3><u>Question 4</u></h3>

Given vertices of ΔLMN:

L = (-6, -4)
M = (-5, -1)
N = (-2 -4)

Given vertices of ΔL'M'N':

L' = (-3, -3)
M' = (-2, 0)
N' = (1, -3)

From inspection of the given diagram, we can see that the two triangles are congruent since their corresponding angles and corresponding side lengths are the same.

There is no apparent reflection or rotation, so the transformation of ΔLMN to ΔL'M'N' is by translation.

To find the mapping rule for the translation, choose one pair of corresponding vertices and determine the difference between the x and y values of the translated point and the original point:

$x_{L'}-x_L =-3-(-6)=3 \implies \textsf{3 units right}$

$y_{L'}-y_L =-3-(-4)=1 \implies \textsf{1 units up}$

Therefore, the mapping rule for the translation is:

$(x,y) \rightarrow (x+3,y+1)$

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1 year ago

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