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2 years ago

Please help me. Thank you

Mathematics

1 answer:

lina2011 [118]2 years ago

5 0

Step-by-step explanation

i had to turn my laptop just to read that

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What is the area of this triangle ?

oee [108]

Answer:

Area of triangle is 9.88 units^2

Step-by-step explanation:

We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

We will use formula:

$Area\,\,of\,\,triangle =\sqrt{s(s-a)(s-b)s-c)} \\where\,\, s = \frac{a+b+c}{2}$

We need to find the lengths of side DE, EF and FD

Length of side DE = a = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side DE = a = $=\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60$

Length of side EF = b = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side EF = b = $=\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8$

Length of side FD = c = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side FD = c = $=\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4$

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle= $=\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88$

So, area of triangle is 9.88 units^2

4 0

2 years ago

Pls help :) i really need to finish it

Licemer1 [7]

Answer:

ok so if equilateral triangle has 1 inch and box has 9 inch of height, the lateral area would be 27 square-inch

Step-by-step explanation:

5 0

1 year ago

0÷2 answer right now 0÷2= right now

77julia77 [94]

0/2=0 because anything divided by zero is zero.

4 0

2 years ago

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What do you call the absolute values of 6 and -6

coldgirl [10]

I believe they are called opposites.

3 0

2 years ago

QUESTION 10

alexandr402 [8]

Answer:

let the grade points be a,b,c

a+b+c=258

b=c+10( since she noticed that on tests two and three,she scored 10 points fewer).

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2 years ago

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