Please help me. Thank you

Can you guys give me a serious answer please?

grin007 [14]

Answer:

800 bacteria

Step-by-step explanation:

Answer of this question depend upon number of hours at the end of day

Let Take Full Day of 24 hrs

Colby bacteria will doubled 12 times ( doubled once in 2hrs => 24/2 = 12)

Colby bacteria at end of day = 50 * 2¹²

Jaquan bacteria will doubled 8 times ( doubled once in 3hrs => 24/3 = 8)

Let say Jaquan bacteria at start of Day = J

Jaquan bacteria at end of day = J * 2⁸

Equating Both

J * 2⁸ = 50 * 2¹²

=> J = 50 * 2⁴

=> J = 50 * 16

=> J = 800

Jaquan will start with 800 Bacteria

4 0

2 years ago

What’s the answer for part A?

jeka57 [31]

The answer is -30 u multiply-3 3/4 by eight because -3 3/4 is one minute and the question is asking for eight minutes

4 0

3 years ago

Which expression is equivalent to the expression shown?

Bess [88]

Answer:

option 3

Step-by-step explanation:

$Formula : a^{-x} = \frac{1}{a^x}$

$3^7 \times 3^{-4} = 3^7 \times \frac{1}{3^4}$

5 0

3 years ago

true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp

Goshia [24]

Answer:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

$\mu = 114, \sigma = 40$

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard deviation for the sampling distribution would be:

$\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4$

So then the answer is TRUE

6 0

3 years ago

at a bargain store, Tanya bought 4 items that each cost the same amount. Tony bought 5 items that each cost the same amount, but

rjkz [21]

1. You can call $x$ to the cost of each one of Tanya's items and $y$ to the cost of each one of Tony's items.