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2 years ago

12 inches is a feet :))

Mathematics

2 answers:

wolverine [178]2 years ago

7 0

i’m with the gàng, I’m with the fleet >:)

quester [9]2 years ago

4 0

Answer:

12 inches is a foot * ;)

Step-by-step explanation:

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Please help, I’ll mark you as brainliest!!!!

Rainbow [258]

Answer:

80%

Step-by-step explanation:

Percent increase is calculated as

$\frac{increase}{original}$ × 100%

Increase = $27 - $15 = $12 , then

percent increase = $\frac{12}{15}$ × 100% = 0.8 × 100% = 80%

5 0

2 years ago

Read 2 more answers

Help me PLEASEEEEEEEEEEEEE

qwelly [4]

Answer:

D. 144

Step-by-step explanation:

find the volume of the shipping container and divide it by the volume of a box.

$2\frac{2}{3}$ × $1$ × $2$ = $\frac{16}{3}$

$\frac{1}{3}$ × $\frac{1}{3}$ × $\frac{1}{3}$ = $\frac{1}{27}$

$\frac{16}{3}$ divided by $\frac{1}{27}$ is 144.

4 0

2 years ago

Please Help me!!! <br><br><br> I know the answer but I don’t understand how to get that answer

worty [1.4K]

-7 ÷ 2 1/2
Okay, so first, put the -7 over one and make 2 1/2 an improper fraction. so now:
-7/1 ÷ 5/2
Then, take the reciprocal of 5/2 and multiply it by -7/1
-7/1 × 5/2
Which would be -35/2

5 0

3 years ago

Which of the following functions is graphed below

Anestetic [448]

D is the answer that is graphed.

4 0

2 years ago

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16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.

Katyanochek1 [597]

We will use the sine and cosine of the sum of two angles, the sine and consine of $\frac{\pi}{2}$ , and the relation of the tangent with the sine and cosine:

$\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta$

$\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0$

$\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}$

If you use those identities, for $\alpha=x,\ \beta=\dfrac{\pi}{2}$ , you get:

$\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x$

$\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x$

Hence:

$\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x$

3 0

3 years ago