Now, let's say, we add "x" lbs of the 60% gold alloy, so.. how much gold is in it? well, is just 60%, so (60/100) * x, or 0.6x.
likewise, if we use "y" lbs of the 40% alloy, how much gold is in it? well, 40% of y, or (40/100) * y, or 0.4y.
now, whatever "x" and "y" are, their sum must be 12.4 lbs.
we also know that the gold amount in each added up, must equal that of the 50% resulting alloy.


how much of the 40% alloy? well, y = 12.4 - x.
Answer:
Following are the solution to the given points:
Step-by-step explanation:
Given values:


Total staff=40
In point a:
To calculate the median number first we arrange the value into ascending order and then collect the even numbers of calls that were also made. Its average of the middle terms is thus the median.
The midterms =55 and 59 so,
Median = 
In point b:
First-quarter

The first quarterlies are 
therefore the multiply of 0.5 by calculating the difference of the 7th and 8th term are:

therefore the it is multiply by the 0.5 for the difference of the 22nd and 23rd term:

In point c:
First decile 

In point d:
quartiles are:

The right answers for the decile are:

As for
will be available.
6 orange. 42 total. 6/42 = 1/7 of the M&Ms are orange.
Answer:
pos: 99. Sor: 17. roq: 64
Step-by-step explanation:
(5x+4)+(x-2)+(3x+7)=180
we add the angles to 180 because straight lines are equal to 180
5x+4+x-2+3x+7=180
5x+x+3x+4-2+7=180
9x+9=180
9x=
9x=171
x=19
then we plug x in
5(19)+4 + (19)-2 +3(19)+7 = 180
angles (left right)
99. 17. 64.
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