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allochka39001 [22]
3 years ago
8

Find an equation of cosine function with maximum of 7, minimum of -7 and period of 7

Mathematics
1 answer:
Galina-37 [17]3 years ago
3 0

Answer:   \bold{y=7cos\bigg(\dfrac{2\pi}{7}x\bigg)}

<u>Step-by-step explanation:</u>

y = A cos (Bx - C) + D

  • A = amplitude (vertical stretch)
  • Period = 2π/B
  • C/B = phase shift
  • D = vertical shift

The minimum is -7 and the max is 7 so A = 7 and D = 0

Period is 7.  Since P = 2π/B then 7 = 2π/B --> B = 2π/7

Nothing was stated about a phase shift so you can use any value for C. I chose C = 0.

Now, input A = 7, B = 2π/7, C = 0, & D = 0 into the equation

y=7\cos\bigg(\dfrac{2\pi}{7}x-0\bigg)+0\\\\\\\text{Simplify}:\\y=7\cos\bigg(\dfrac{2\pi}{7}x\bigg)

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A car leaves its garage and travels for 30km on a bearing of 145, then 10 km on a bearing of 250 Calculate a) the distance trave
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The distance travelled from the starting point is 29 km , the bearing is 344 degree

The missing diagram is attached with the answer.

<h3>What is Bearing Angle ?</h3>

It is the horizontal angle between the object and another object.

It is given that the car starts from point travels for 30km on a bearing of 145, then 10 km on a bearing of 250

(a) the distance travelled from the starting point

It can be understood from the diagram that

To determine the distance , b is to determined4

By applying Cosine rule

b² = a² +c²-2ac cos\rm \theta

b² = 10²  +30²  - 2* 30*10 cos75

b² = 100+900 -600* 0.2588

b² = 100-155.2914

b² = 844.7

b = 29 km

Therefore the distance travelled from the starting point is 29 km.

(b) the bearing of the starting point from the car.

To determine the bearing ,

angle C has to be determined

By sine rule

sin C / c = sin B / b

sin C = sin 75 * 30 / 29

sin C = 0.9970

C = sin⁻¹ 0.9970

C = 85.59 degree

angle C = α +70 degree

α  = 15.59 degree

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To know more about Bearing

brainly.com/question/9214012

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Find x please so difficult
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Attached is a screenshot.

y = 180 - 50 - 70 = 60.

x + y = 180, so x = 120

Remember to try to use parallel lines when you can

The second uses the same method, just the opposite side.

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