Answer:
The measure of ∠BDA is 30 Degrees.
Step-by-step explanation:
Lets construct a trapezium with the given data
If O is the point of intersection of the diagonals, ∆ AOD ~ ∆COB. Then
On substituting the given values
![\frac{ AO}{7} = \frac{CO}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B%20AO%7D%7B7%7D%20%3D%20%5Cfrac%7BCO%7D%7B5%7D)
Also we know that AC = 6 . That is
AO + OC = 6 or OC = 6 - AO
substituting for CO and cross multiply
5·AO = (6-AO)·7
5AO = 42 - 7AO
12AO = 42
AO =
= 3.5
All of the angles at E are right angles, so
has the trigonometric ratio
=
= 0.5 = ![\frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D)
∠BDA = arcsin(1/2) = 30°
The correct answer for first one is,
![- 390625 {p}^{5}](https://tex.z-dn.net/?f=%20-%20390625%20%7Bp%7D%5E%7B5%7D%20)
The correct answer for second one is,
![4 {x}^{3} {4}^{y}](https://tex.z-dn.net/?f=4%20%7Bx%7D%5E%7B3%7D%20%20%7B4%7D%5E%7By%7D%20)
I hope this helps.
have a nice day/night.
A números irracionais maiores que 3,5 é menores que 3