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Aleks04 [339]
3 years ago
6

Can one please help me with this question

Mathematics
2 answers:
Nostrana [21]3 years ago
8 0

Answer:

254.34 cm^2

Step-by-step explanation:

Volume of cylinder = \pi r^{2} h

We know that the diameter is 6, which means that the radius is 3 cm.

Now, it also tell us that that the height is triple the radius, this means that we multiply it by 3. Therefore, the height is 9 cm.

Now we know r = 3 cm and h = 9 cm, pi is assumed to 3.14 as well.

Substituting into the formula we will end up with 254.34 cm^2.

yuradex [85]3 years ago
8 0
254.34
Is the answers
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Ben is 5 years less than 3 times Gracie's age. How can that be represented as an expression?<br>  
Tanzania [10]
You can write 5 times 3
7 0
3 years ago
When e = 4, f = 2, and g = 8If e varies jointly with f and g, what is the constant of variation?
tatyana61 [14]

Answer:

e=\frac{1}{4} fg

Step-by-step explanation:

Joint variation problem  solve using the equation y = kxz.

e ∝ fg

e=kfg

now substitute the values

4=k*2*8\\4=16k\\k=\frac{4}{16} \\k=\frac{1}{4}

The relationship will be:

e=kfg\\e=\frac{1}{4} fg

8 0
3 years ago
Read 2 more answers
Mel used partial quotients to find the quotient of 378 divided by 3.What could be the partial quotient that Mel found?
Genrish500 [490]

Answer:

The partial quotients are 100, 20 and 6. The quotient is 126.

Step-by-step explanation:

The dividend is 378 and the divisor is 3.

First find the factors of 3, near to 300.

3\times 1=3

3\times 10=30

3\times 100=300

The value 300 is less than 378, so record the partial quotient 100 and subtract 300 from 378. Repeat the same process until the dividend has been zero.

Now the remaining divide is 78.

First find the factors of 3, near to 78.

3\times 20=60

3\times 30=90

Since 90>78, therefore 30 is not a partial quotient. The value 60 is less than 78 , so record the partial quotient 20 and subtract 60 from 78.

Now the remaining divide is 18.

3\times 6=18

The number 6 is a partial quotient.

Therefore  partial quotients are 100, 20 and 6. Add the partial quotient to find quotient.

100+20+6=126

3 0
4 years ago
Imagine an experiment having three conditions and 20 subjects within each condition. The mean and variances of each condition ar
xxTIMURxx [149]

Answer:

1. Mean square B= 5.32

2. Mean square E= 16.067

3. F= 0.33

4. p-value: 0.28

Step-by-step explanation:

Hello!

You have the information of 3 groups of people.

Group 1

n₁= 20

X[bar]₁= 3.2

S₁²= 14.3

Group 2

n₂= 20

X[bar]₂= 4.2

S₂²= 17.2

Group 3

n₃= 20

X[bar]₃= 7.6

S₃²= 16.7

1. To manually calculate the mean square between the groups you have to calculate the sum of square between conditions and divide it by the degrees of freedom.

Df B= k-1 = 3-1= 2

Sum Square B is:

∑ni(Ÿi - Ÿ..)²

Ÿi= sample mean of sample i ∀ i= 1,2,3

Ÿ..= general mean is the mean that results of all the groups together.

General mean:

Ÿ..= (Ÿ₁ + Ÿ₂ + Ÿ₃)/ 3 = (3.2+4.2+7.6)/3 = 5

Sum Square B (Ÿ₁ - Ÿ..)² + (Ÿ₂ - Ÿ..)² + (Ÿ₃ - Ÿ..)²= (3.2 - 5)² + (4.2 - 5)² + (7.6 - 5)²= 10.64

Mean square B= Sum Square B/Df B= 10.64/2= 5.32

2. The mean square error (MSE) is the estimation of the variance error (σ_{e}^2 → S_{e} ^{2}), you have to use the following formula:

Se²=<u> (n₁-1)S₁² + -(n₂-1)S₂² + (n₃-1)S₃²</u>

                        n₁+n₂+n₃-k

Se²=<u> 19*14.3 + 19*17.2 + 19*16.7 </u>= <u>  915.8   </u>  = 16.067

                 20+20+20-3                  57

DfE= N-k = 60-3= 57

3. To calculate the value of the statistic you have to divide the MSB by MSE

F= \frac{Mean square B}{Mean square E} = \frac{5.32}{16.067} = 0.33

4. P(F_{2; 57} ≤ F) = P(F_{2; 57} ≤ 0.33) = 0.28

I hope you have a SUPER day!

3 0
3 years ago
Solve by inspection: X+4=15
amid [387]

x + 4 = 15

- 4        -4

x = 11

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7 0
4 years ago
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