Answer:
y=3x.........1
y=x^2-10.......2
substituting value of eq 1 to 2
3x=x^2-10
x^2-10-3x=0
x^2-3x-10=0
x^2-5x+2x-10=0
X(x-5)+2(x-5)=0
(x-5)(X+2)=0
then
X=5 or X=-2
again
y=??
when X=5
y=3×5=15
when X=-2
y=-6
Answer:
B
Step-by-step explanation:
We can see in the expression that there are 2 x² blocks, 4 -x blocks, and 3 -1 blocks. Therefore, we can write this as
2 * x² + 4 * (-x) + 3 * (-1) = 2x²-4x-3
Comparing this with each answer, we have
A: x²-2x-4 + x² + 2x-1 = 2x²-5. This is not correct
B: 3x²-7x+1-(x²-3x+4) = 3x²-7x+1 -x²+3x-4 = 2x²-4x-3. This seems correct but we can check the other answers to be sure
C: (2x+1)(x-3) = 2x²-6x+x-3 = 2x²-5x-3. This is incorrect
D:
. This is incorrect
No, it won’t work. The greatest common factor between 45 and 27 is 9, but 45-27=18. So it cannot work.
(4,5),(-3,-1)
slope = (-1 - 5) / (-3 - 4) = -6/-7 = 6/7
y - y1 = m(x - x1)
slope(m) = 6/7
using points (-3,-1)...x1 = -3 and y1 = -1
now we sub...pay attention to ur signs
y - (-1) = 6/7(x - (-3) =
y + 1 = 6/7(x + 3) <===