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riadik2000 [5.3K]
3 years ago
9

Steven has a small business that provides computer application training and data entry support services. He earns $25 per hour f

or training and $15 per hour for data entry support. Steven can work no more than 40 hours a week. He wants to use linear programming techniques to optimize his income.
Mathematics
1 answer:
zlopas [31]3 years ago
5 0

Answer:

Step-by-step explanation:

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0.3721 or 37.21%

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P(I) = 0.60; P(II) = 0.40;

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The probability that the phone came from factory II, given that is not defective, is determined by the probability of a phone from factory II not being defective divided by the probability of a phone not being defective.

P(II|not) = \frac{P(II)*P(not_{II})}{P(II)*P(not_{II})+P(I)*P(not_{I})}\\P(II|not) = \frac{0.40*0.80}{0.40*0.80+0.60*0.90}\\ P(II|not) =0.3721 = 37.21\%

The probability is 0.3721 or 37.21%.

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