If you are asking if 2x3=15 if it it always true, sometimes true, or never true
the answer would be never true because 2x3 will always equal 6. 2x3 will never ever equal 15.
I hope this helps!
Answer:
y = 3/2
Step-by-step explanation:
5(2y - 1) - 2(3y) = 1
First we use distributive property:
10y - 5 - 6y = 1
because 5 × 2y = 10y
and -2 × 3y = -6y
Now we combine the like terms:
4y -5 = 1
because 10y - 6y = 4y
Now we have to send the -5 to the other side. (when we send it to the other side it becomes positive because right now it is negative)
4y = 1 + 5
Again we combine the like terms:
4y = 6
(because 5 + 1 = 6)
Now we have to send the 4 to the other side because we need to get the y value. (when we send it to the other sidr it will be divided)
y = 6/4
and we simplify:
y = 3/2
And we cannot simplify or do anything else. So that is the answer.
Hope that helped!
So the board is divided into 5 pieces, and 2/5 of the board is left. The leftovers equal 4 originals. This is equal to 4 times 5.
equation:
2/5(5x)=20
2x=20
x=10
He started with 10 boards.
Hope this helps!
Answer:
-31
Step-by-step explanation:
2x - abs(4 - 7x)
2x = 2 * - 3 = - 6
4 - 7x = 4 - 7*-3 = 4 + 21 = 25
-6 - abs(25)
-6 - 25 = -31
You should note three things.
1. the absolute value of 25 is 25
2. There is a - sign outside the influence of the 25 so 25 becomes - 25
3. - 6 - 25 = - 31
Answer:
D. about 8.5 mi
Step-by-step explanation:
To go from Aesha to Josh, you go 6 units right and 6 units up.
Each unit is a mile, so you go 6 miles right and 6 miles up.
Think of each 6 mile distance as a leg of a right triangle, and the direct distance from one place to the other as the hypotenuse of the right triangle. Use the Pythagorean theorem to find the length of the hypotenuse.
a^2 + b^2 = c^2
The 6-mile legs are a and b. c is the hypotenuse.
(6 mi)^2 + (6 mi)^2 = c^2
c^2 = 36 mi^2 + 36 mi^2
c^2 = 72 mi^2
c = sqrt(72) mi
c = sqrt(36 * 2) mi
c = 6sqrt(2) mi
c = 6(1.4142) mi
c = 8.5 mi
