Answer:
yo i would help but my brain jus farted jus by lookin at it
Step-by-step explanation:
Answer:
Mason has
- 16 20¢ stamps;
- 25 3¢ stamps;
- 40 49¢ stamps.
Step-by-step explanation:
Let x be the number of 20¢ stamps, then the number of 3¢ stamps is x + 9.
Mason has 56 total 49¢ and 20¢ stamps, then the number of 49¢ stamps is 56 - x.
Amounts:
- in 49¢:
cents; - in 20¢:
cents; - in 3¢:
cents.
Total amount:

- $23.55.
Hence,

Mason has
- 16 20¢ stamps;
- 25 3¢ stamps;
- 40 49¢ stamps.
Answer:
4000×.06×2 which is 480
Step-by-step explanation:
You must times the money by the ir and then the year. Or money times the year then ir, it wouldn't really matter as long you times the three of them together
Answer:
13
Step-by-step explanation:

Hope this helps.