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3 years ago

Which inequality is true? Use the number line to help.

Mathematics

1 answer:

jolli1 [7]3 years ago

4 0

Answer:

c. -1.5 < -0.5

Step-by-step explanation:

a. -1.5 > 0.5 . . . . false

b. -0.5 > 0 . . . . . false

c. -1.5 < -0.5 . . . TRUE

d. 1/2 > 0.5 . . . . false (these are the same number) 1/2 = 0.5

_____

In order on the number line from left to right, you will see ...

(left end) ... -1.5 ... -0.5 ... 0 ... 0.5 ... (right end)

The inequality relation appropriate to these is ...

(number on the left) < (number on the right)

Of course, this can be swapped around so you have ...

(number on the right) > (number on the left)

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Answer this question please and thank you

Murljashka [212]

Answer:

Step-by-step explanation:

here´s and example for 1

1⁵

1x1x1x1x1=1

so 1 raised to the power of any number is 1

1 multiply by itself any number of times is 1

here´s an example for 0

0⁴

0x0x0x0=0

hence, the vale of 0 raised to any power is 0.

0 multiplied by itself any number of times is 0

8 0

2 years ago

What I the slope of the equation of the line below.

Goshia [24]

Answer:

<h2>the slope m = 3</h2>

Step-by-step explanation:

Look at the picture.

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

From the graph we have the points (0, 4) and (-2, -2). Substitute:

$m=\dfrac{-2-4}{-2-0}=\dfrac{-6}{-2}=3$

5 0

3 years ago

Read 2 more answers

Five friends had lunch together. Their lunch bill included these amounts: $8.79, $5.15, $11.73, $2.49, and $9.05. Estimate the t

WARRIOR [948]

Answer:

Step-by-step explanation:

all those numbers added equals 37.21

front end estimation is where you round to the first number on the left just ignore the decimal point in this case. so the answer would be 40

7 0

3 years ago

(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul

Aloiza [94]

Answer

(a) $F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

Step-by-step explanation:

(a) $f(t) = 20.5 + 10t + t^2 +$ δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 f(s)e^{-st} \, dt$

where a = ∞

=> $F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt$

where d(t) = δ(t)

=> $F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt$

Integrating, we have:

=> $F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3} )\left \{ {{a} \atop {0}} \right.$

Inputting the boundary conditions t = a = ∞, t = 0:

$F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $f(t) = e^{-t} + 4e^{-4t} + te^{-3t}$

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt$

$F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt$

$F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt$

Integrating, we have:

$F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.$

Inputting the boundary condition, t = a = ∞, t = 0:

$F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

3 0

2 years ago

In the diagram, the circle will be dilated by a scale factor of 3 about the origin. The points C, A, and B map to C', A', and B'

stellarik [79]

Original coordinates of the points:
A (8,15) ; B (12,13) ; C (8,10)

Dilated scale factor of 3.

A ⇒ 3x = 3(8) = 24 ; 3y = 3(15) = 45 ⇒ A' (24,45)
B ⇒ 3x = 3(12) = 36 ; 3y = 3(13) = 39 ⇒ B' (36, 39)
C ⇒ 3x = 3(8) = 24 ; 3y = 3(10) = 30 ⇒ C' (24, 30)

The given image forms a right triangle. So, I'll get the short leg and long leg of the right triangle to solve for the hypotenuse, length of CB.

Short leg: y value of B and C
39 - 30 = 9

Long leg: x value of B and C
36 - 24 = 12

a² + b² = c²
9² + 12² = c²
81 + 144 = c²
225 = c²
√225 = √c²
15 = c

The length of CB is 15 units.

4 0

3 years ago