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slava [35]
3 years ago
12

Which inequality is true? Use the number line to help.

Mathematics
1 answer:
jolli1 [7]3 years ago
4 0

Answer:

  c. -1.5 < -0.5

Step-by-step explanation:

a. -1.5 > 0.5 . . . . false

b. -0.5 > 0 . . . . . false

c. -1.5 < -0.5 . . . TRUE

d. 1/2 > 0.5 . . . . false (these are the same number) 1/2 = 0.5

_____

In order on the number line from left to right, you will see ...

  (left end) ... -1.5 ... -0.5 ... 0 ... 0.5 ... (right end)

__

The inequality relation appropriate to these is ...

  (number on the left) < (number on the right)

Of course, this can be swapped around so you have ...

  (number on the right) > (number on the left)

You might be interested in
HELPPPPPPPPPPPPPPPPPPP
Ipatiy [6.2K]

Answer:

C

Step-by-step explanation:

(f + g)(x) = f(x) + g(x)

f(x) + g(x)

= - 4x² - 6x - 1 + (- x² - 5x + 3) ← remove parenthesis

= - 4x² - 6x - 1 - x² - 5x + 3 ← collect like terms

= - 5x² - 11x + 2 → C

5 0
3 years ago
A phone manufacturer wants to compete in the touch screen phone market. Management understands that the leading product has a le
frutty [35]

Answer:

a) Null hypothesis:\mu_{1} - \mu_{2} \leq 120

Alternative hypothesis:\mu_{1} - \mu_{2}>120

b) Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{(485-340)-120}{\sqrt{\frac{55^2}{100}+\frac{30^2}{120}}}}=4.0689  

c) Critical value

The first step is calculate the degrees of freedom, on this case:

df=n_{1}+n_{2}-2=100+120-2=218

The significance level on this case is 0.05 or 5% so we need to find a quantile on the t distribution with 218 degrees of freedom that accumulates 0.95 of the area on the left and 0.05 of the area on the right tail and this value can be founded with the following excel code: "=T.INV(1-0.05,218)" and we got:

t_{crit}= 1.652

Conclusion

Since our calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 5% of significance and then we can conclude that the new product has a battery life more than two hours (120 minutes) longer than the leading product

Step-by-step explanation:

Data given and notation

\bar X_{1}= 8*60 +5 =485 represent the mean for the new sample

\bar X_{2}=5*60+40=340 represent the mean for the old sample

s_{1}=55 represent the sample standard deviation for the new sample

s_{2}=30 represent the sample standard deviation for the old sample

n_{1}=100 sample size selected for the new sample

n_{2}=120 sample size selected for the old sample

\alpha=0.05 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

a) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the new product has a battery life more than two hours longer than the leading product., the system of hypothesis would be:

Null hypothesis:\mu_{1} - \mu_{2} \leq 120

Alternative hypothesis:\mu_{1} - \mu_{2}>120

If we analyze the size for the samples both are higher than 30 but we don't know the population deviations so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{(\bar X_{1}-\bar X_{2})- \Delta}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

b) Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{(485-340)-120}{\sqrt{\frac{55^2}{100}+\frac{30^2}{120}}}}=4.0689  

c) Critical value

The first step is calculate the degrees of freedom, on this case:

df=n_{1}+n_{2}-2=100+120-2=218

The significance level on this case is 0.05 or 5% so we need to find a quantile on the t distribution with 218 degrees of freedom that accumulates 0.95 of the area on the left and 0.05 of the area on the right tail and this value can be founded with the following excel code: "=T.INV(1-0.05,218)" and we got:

t_{crit}= 1.652

Conclusion

Since our calculated value is higher than the critical value we have enough evidence to reject the null hypothesis at 5% of significance and then we can conclude that the new product has a battery life more than two hours (120 minutes) longer than the leading product

7 0
3 years ago
Please help me ive never done one like this
inessss [21]

Given:

DE = (6x - 9) cm

EF = (4x + 4) cm

LM = 14 cm

MN = 16 cm

To find:

The value of x.

Solution:

<em>If three or more parallel lines intersect two transversals, then they cut off the transversals proportionally.</em>

$\Rightarrow \frac{DE}{EF} =\frac{LM}{MN}

$\Rightarrow \frac{6x-9}{4x+4} =\frac{14}{16}

Do cross multiplication.

$\Rightarrow 16( {6x-9})=14 ({4x+4} )

$\Rightarrow 96x-144=56 x+56

Add 144 on both sides.

$\Rightarrow 96x-144+144=56 x+56+144

$\Rightarrow 96x=56 x+200

Subtract 56x from both sides.

$\Rightarrow 96x-56x=56 x+200-56x

$\Rightarrow 40x=200

Divide by 40 on both sides, we get

$\Rightarrow x=5

The value of x is 5.

5 0
3 years ago
Mrs.Bailey had 15 pieces of candy. She gave away some candy and has 3 pieces left. What is the percent decrease of candy?
Alenkasestr [34]

Answer:

12

Step-by-step explanation:

subtract 15 away from 3 and you have 12 so that how Mrs. Bailey has 3 pieces of candy left

3 0
3 years ago
Read 2 more answers
Please help me i have limited time and im confused
luda_lava [24]
The expected value is $8,000.
4 0
2 years ago
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