Find the volume of Prism A.

Consider a chemical company that wishes to determine whether a new catalyst, catalyst XA-100, changes the mean hourly yield of i

kolezko [41]

Answer:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

Step-by-step explanation:

Data given and notation

Data: 801, 814, 784, 836,820

We can calculate the sample mean and sample deviation with the following formulas:

$\bar X =\frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}$

$\bar X=811$ represent the sample mean

$s=19.647$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =750$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is different from 750 pounds per hour, the system of hypothesis would be:

Null hypothesis: $\mu = 750$

Alternative hypothesis: $\mu \neq 750$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{811-750}{\frac{19.647}{\sqrt{5}}}=6.943$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

What do you conclude?

Compute the p-value

Since is a two tailed test the p value would be:

$p_v =2*P(t_{4}>6.943)=0.00226$

If we compare the p value and a significance level assumed $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is significantly different from 750 pounds per hour.

4 0

3 years ago

Simplify the expression (5k^2)^3 5k^6 5k^8 125k^5 125k^6

o-na [289]

(5k²)³
(5³)(k²)³
125k⁶

The answer is D.

6 0

3 years ago

I REALLY NEED HELP FAST I WILL GIVE BRAINLYEST

svetoff [14.1K]

Answer:

In common scientific notation, any nonzero quantity can be expressed in two parts: sufficient whose absolute value is greater than or equal to 1 but less than 10, and a power of 10 by which the coefficient is multiplied. In some writings, the coefficients are closer to zero by one order of magnitude. In this scheme, any nonzero quantity is expressed in two parts: a coefficient whose absolute value is greater than or equal to 0.1 but less than 1, and a power of 10 by which the coefficient is multiplied. The quantity zero is denoted as 0 unless precision is demanded, in which case the requisite number of significant digits are written out

4 0

2 years ago

36x+72xy+27xy factor the expression.

nexus9112 [7]

Answer:

9x(4+8y+3y)

Step-by-step explanation:

36x+72xy+27xy

9x(4+8y+3y)

4 0

3 years ago

why was the value of y for the function y =5x + 1 always be greater than that for the function y=4x+2 when x>1

Galina-37 [17]

Lets compare both equations so we can explain the reason for it, and see it clearly:
y1 = 5x + 1
y2 = 4x + 2
y1 > y2
5x + 1 > 4x + 2
To see why that happens we need to solve for x:
5x - 4x > 2 - 1
x > 1
Therefore, the first equation is greater than the second for values of x > 1

6 0

3 years ago