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3 years ago

I will be asking questions constantly to finish a class

Mathematics

1 answer:

blagie [28]3 years ago

7 0

Answer:

Step-by-step explanation:

so it has to go down,cross 0,-7, and then go up

y-axis is vertical

and since its a negative it would be in the lower quadrants

pls mark me brainliest

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Given that ∠ABC ≅ ∠DBE, which statement must be true?

STALIN [3.7K]

The second one which is ABD = CBE is the correct one

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4 years ago

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3.In 1995, the Educational Testing Service in Princeton, New Jersey (which administers SAT exam) re-centered the scores so that

Travka [436]

Answer:

38.22% probability that of 10 randomly selected students, lessthan four will be between 900 and 1,100

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they score between 900 and 1,100, or they score outside this range. The probability of a student scoring between 900 and 1,100 is independent from other students. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

About 40 percent of these students’ scores were between 900 and 1,100.

This means that $p = 0.4$ .

a)Based on this estimate, what is the probability that of 10 randomly selected students, lessthan four will be between 900 and 1,100?

This is $P(X < 4)$ when $n = 10$ . So

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{10,0}.(0.4)^{0}.(0.6)^{10} = 0.0060$

$P(X = 1) = C_{10,1}.(0.4)^{1}.(0.6)^{9} = 0.0403$

$P(X = 2) = C_{10,2}.(0.4)^{2}.(0.6)^{8} = 0.1209$

$P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.2150$

$P(X < 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0060 + 0.0403 + 0.1209 + 0.2150 = 0.3822$

38.22% probability that of 10 randomly selected students, lessthan four will be between 900 and 1,100

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4 years ago

1. (10 pts.) Suppose you have a language with only 3 letters: A, B, and C, which occur with frequencies 0.7, 0.2, and 0.1, respe

butalik [34]

Answer:

The solution to this question is attached below:

3 0

3 years ago

Find the product. (0.5n^5)^2(10n^7)^3

never [62]

Answer:

250{n}^{31}

Step-by-step explanation:

$(0.5 {n}^{5} )^{2} (10 {n}^{7} )^{3} \\ = (0.5)^{2}{n}^{5 \times 2} \times (10)^{3} {n}^{7 \times 3} \\ = 0.25{n}^{10} \times 1000{n}^{21} \\ = 0.25 \times 1000 {n}^{10 + 21} \\ = 250{n}^{31}$

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3 years ago

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In the figure, angle A measures 41° and angle D measures 32°. What is the measurement of angle E?

Jlenok [28]

Interior angles of a triangle, when added, = 180
so < A + < B + < C = 180
41 + 90 + < C = 180
131 + < C = 180
< C = 180 - 131
< C = 49

< C + < D + < E = 180.....because when added they form a line
49 + 32 + < E = 180
81 + < E = 180
< E = 180 - 81
< E = 99 <======

3 0

3 years ago

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I will be asking questions constantly to finish a class​

I will be asking questions constantly to finish a class