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3 years ago

Compare the rates to find which is the best value.

Mathematics

1 answer:

sattari [20]3 years ago

5 0

Answer:

C6 greeting cards for $23.40

Step-by-step explanation:

A. 13.5/3=4.5

B. 38.25/9=4.25

C. 23.4/6=3.9

d. 32.8/8=4.1

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What’s the x axis of -4x+8y=-16

balu736 [363]

Answer:

Step-by-step explanation:

When need to find x axis y is =0

So now you can find x

The answer of x is equally to the xaxis.

If need to find y axis then please let x =0.

4 0

3 years ago

A lamina with constant density rho(x, y) = rho occupies the given region. Find the moments of inertia Ix and Iy and the radii of

jenyasd209 [6]

Answer:

Ix = Iy = $\frac{ρπR^{4} }{16}$

Radius of gyration x = y = $\frac{R}{4}$

Step-by-step explanation:

Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.

Mass of disk = ρπR2

Moment of inertia about its perpendicular axis is $\frac{MR^{2} }{2}$ . Moment of inertia of quarter disk about its perpendicular is $\frac{MR^{2} }{8}$ .

Now using perpendicular axis theorem, Ix = Iy = $\frac{MR^{2} }{16}$ = $\frac{ρπR^{4} }{16}$ .

For Radius of gyration K, equate MK2 = MR2/16, K= R/4.

3 0

3 years ago

Find the expressions for x=6 and y=17 x ÷ 3 + y

hjlf

19 because 6 divided by 3 = 2 + 17 ?

3 0

3 years ago

Read 2 more answers

A phone company charges $0.06 per minute for local calls and $0.15 per minute for international calls. When your bill comes, it

solmaris [256]

Let's assume two variables x and y which represent the local and international calls respectively.

x + y = 852 = total number of minutes which were consumed by the company (equation 1)
0.06*x+ 0.15 y =69.84 = total price which was charged for the phone calls (Equation 2)
from equation 1:-
x=852 -y (sub in equation 2)
0.06 (852 - y) + 0.15 y =69.84

51.12 -0.06 y +0.15 y =69.84 (subtracting both sides by 51.12)
0.09 y =18.74
y= 208 minutes = international minutes (sub in 1)
208+x=852 (By subtracting both sides by 208)
x = 852-208 = 644 minutes = local minutes

6 0

3 years ago

As part of a research project on student debt at TWU, a researcher interviewed a sample of 35 students that were chosen at rando

Inga [223]

Answer:

Option a is right

Step-by-step explanation:

Given that as part of a research project on student debt at TWU, a researcher interviewed a sample of 35 students that were chosen at random concerning their monthly credit card balance.

Sample average = 2573

Variance = 4252

Sample size = 35

STd deviation of X = $\sqrt{4252} \\=65.21$

Score of student selected at random X=1700

Corresponding Z score = $\frac{1700-2573}{65.201} \\=-13.38$

Rounding of we get Z score = -13.4

option a is right

6 0

3 years ago