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Elis [28]
3 years ago
9

Which is the last operation performed when evaluating (8 minus 2 x) squared + 4 for x = 3?

Mathematics
2 answers:
MrRa [10]3 years ago
8 0

Your answer would most definitely be addition!

kompoz [17]3 years ago
4 0

Answer:

addition

Step-by-step explanation:

The given expression is (8-2x)^2+4

We want to determine the last operation performed when evaluating this expression for x=3.

We substitute to get:

(8-2*3)^2+4

Multiply within the parenthesis to get:

(8-6)^2+4

Subtract to get:

2^2+4

Evaluate the exponent to get:

4+4

Add to obtain:

8

Hence the final operation is addition

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linda scored 35, 47, and 42 points on three tests. how many points should she get on the fourth test to get an average score of
aliya0001 [1]
(35 + 47 + 42 + x) / 4 = 50
(124 + x) / 4 = 50....multiply both sides by 4, cancelling the 4 on the left side.
124 + x = 50 * 4
124 + x = 200
x = 200 - 124
x = 76 <===
6 0
3 years ago
(7z^3+42z^2-15z+1)- (36z^2+12z-21)​
My name is Ann [436]

Answer:

7z^3+6z^2-27z+22

Step-by-step explanation:

The given question is of subtraction:

So,

(7z^3+42z^2-15z+1)- (36z^2+12z-21)​

=7z^3+42z^2-15z+1-36z^2-12z+21

Combining alike terms to simplify

=​7z^3+42z^2-36z^2-15z-12z+1+21

=7z^3+6z^2-27z+22

So the answer in simplified form is:

7z^3+6z^2-27z+22 ..

6 0
3 years ago
Read 2 more answers
Who drove faster? Trevor drove 202 miles in 4 hours Maggie drove 330 miles in 6 hours Nev drove 412 miles in 8 hours Juanita dro
Roman55 [17]

Answer:

Maggie

Step-by-step explanation:

So trevor drove 50.5mph bc 202/4

Maggie 330/6 = 55mph

Nev 412/8=51.5mph

Juanita 261/5= 52.2mph


7 0
3 years ago
CAN SOMEONE HELP EXPLAIN THIS TO ME !!!!
Jet001 [13]
The quadratic formula is above.

You want each equation in standard form: ax^2 + bx + c = 0
I begin each problem by defining variables.
For instance 3. Is in standard form. X^2 -2x - 3 = 0. a = 1, b = -2, c = -3

Now use quadratic formula: x = [- b + or - sqrt(b^2 - 4ac)]\2a

8 0
3 years ago
(e+3)(e-5) expanded and simplified
Zarrin [17]

Step-by-step explanation:

(e + 3)(e - 5) \\ e \times e + e \times  ( - 5) + e \times e + e \times 3 \\  { e}^{2}  + ( - 5e) +  {e}^{2}  + 3e \\  {2e}^{2}  + ( - 2e)

In this type of math equation, you have to multiply all members from the first part with the second part.

Expanded:

e \times e+e \times (-5)+e \times e+e \times 3

simplified:

{2e}^{2}  + ( - 2e)

8 0
2 years ago
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