Question

Which is the last operation performed when evaluating (8 minus 2 x) squared + 4 for x = 3?

Answer 1

Your answer would most definitely be addition!

Answer 2

Answer:

addition

Step-by-step explanation:

The given expression is $(8-2x)^2+4$

We want to determine the last operation performed when evaluating this expression for x=3.

We substitute to get:

$(8-2*3)^2+4$

Multiply within the parenthesis to get:

$(8-6)^2+4$

Subtract to get:

$2^2+4$

Evaluate the exponent to get:

4+4

Add to obtain:

8

Hence the final operation is addition