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2 years ago

Find the product of 619 x 37

Mathematics

2 answers:

Anettt [7]2 years ago

8 0

The product of 619 x 37 is 22,903

Vikki [24]2 years ago

3 0

Answer:

22903

Step-by-step explanation:

$619\cdot 37=22903$ . Hope this helps!

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What is the genral form of (x-6)2+(y-4)2=56

dusya [7]

X+y=38 that’s your answer

5 0

2 years ago

((81x^3 y^(-1/3))^1/4)/(x^2 y)^1/4 simplify

malfutka [58]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}
\\\\\\
\left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}\\\\
-------------------------------\\\\$

$\bf \cfrac{\left( 81x^3y^{-\frac{1}{3}} \right)^{\frac{1}{4}}}{(x^2y)^{\frac{1}{4}}}\implies \cfrac{81^{\frac{1}{4}}x^{3\cdot {\frac{1}{4}}}y^{-\frac{1}{3}\cdot {\frac{1}{4}}}}{x^{2\cdot {\frac{1}{4}}}y^{\frac{1}{4}}}\implies
\cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}y^{-\frac{1}{12}}}{x^{\frac{2}{4}} y^{\frac{1}{4}}}$

$\bf \cfrac{81^{\frac{1}{4}}x^{\frac{3}{4}}x^{-\frac{2}{4}}}{ y^{\frac{1}{4}}y^{\frac{1}{12}}}\implies \cfrac{(3^4)^{\frac{1}{4}}x^{\frac{3}{4}-\frac{2}{4}}}{y^{\frac{1}{4}+\frac{1}{12}}}\implies \cfrac{3^{4\cdot \frac{1}{4}}x^{\frac{1}{4}}}{y^{\frac{4}{12}}}\implies \cfrac{3^{\frac{4}{4}}x^{\frac{1}{4}}}{y^{\frac{1}{3}}}
\\\\\\
\cfrac{3\sqrt[4]{x}}{\sqrt[3]{y}}$

7 0

2 years ago

Given PQRS and ZS = 40°, what is the measure of ZR?<br> S<br> R<br> 40°

morpeh [17]

it is 140° Bc angle S and Z should add up to 180

7 0

2 years ago

Read 2 more answers

Please help!! I’ll give branliest!!!

Ostrovityanka [42]

Answer:

4.88

Step-by-step explanation:

sinA=opposite/adjacent

sin24=x/12

12(0.40673664307)=x

x=4.88083971691

4 0

2 years ago

Find the Simple Interest<br> $700 deposited at an interest rate of 1.5% for 3 years

slega [8]

Answer:

$31.50

Step-by-step explanation:

First, converting R percent to r a decimal

r = R/100 = 1.5%/100 = 0.015 per year,

then, solving our equation

I = 700 × 0.015 × 3 = 31.5

I = $ 31.50

The simple interest accumulated

on a principal of $ 700.00

at a rate of 1.5% per year

for 3 years is $ 31.50.

3 0

2 years ago