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Natasha2012 [34]
3 years ago
7

(08.02)

Mathematics
1 answer:
alukav5142 [94]3 years ago
8 0

Answer:

the median is 80.5

Step-by-step explanation:

first we put them in order

75,76,77,79,80,81,85,86,90,91

the median is the middle number...however, in cases where there are an even number of numbers, ur gonna have 2 middle numbers....so u take the average of those 2 numbers...basically, u add them and divide by 2.

So we have 2 numbers in the middle.....we add them and divide by 2 to get the median.

(80 + 81) / 2 = 161/2 = 80.5 <== the median

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Which set of number may represent the lengths of side lengths?
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Answer:

7,8,1

Step-by-step explanation:

you have to know how much is a lengths

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What are the approximate solutions of 7x^2 4x-9=0??
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No solution 7x square and -3 cant equal you a positive or a negative answer

8 0
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Help pls .. Given that a student has a sibling, what is the likelihood that he or she does
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Answer:

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Step-by-step explanation:

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4 0
2 years ago
Read 2 more answers
I need help , if yk the answer help fr!!!
Feliz [49]

Answer:

The measure of the angle JKG is:

m∠JKG = 56°

Step-by-step explanation:

<u>Given</u>

m∠JKG = 76-2x

m∠FHK = 6x-4

J is a midpoint of the segment FG and K is a midpoint of the segment GH.

<u>To determine</u>

m∠JKG = ?

Given that J is a midpoint of the segment FG and K is a midpoint of the segment GH. Thus, making two similar triangles, ΔJGK and ΔFGH

We know that two triangles are similar if the only difference is size. So, the angles remain the same.

so m∠JKG and m∠FHK are equal.

i.e.

m∠JKG = m∠FHK

substitute m∠JKG = 76-2x and m∠FHK = 6x-4

76-2x = 6x-4

6x+2x = 76 + 4

8x = 80

divide both sides by 8

8x/8 = 80/8

x = 10

Therefore, the value of x = 10

As

m∠JKG = 76-2x

substitute x = 10

m∠JKG = 76 - 2(10)

             = 76 - 20

             = 56°

Therefore, measure of the angle JKG is:

m∠JKG = 56°

4 0
2 years ago
FIND THE DISTANCE BETWEEN THE POINTS. ROUND THE ANSWER TO TWO DECIMAL POINTS (3,2) (8,2)
defon

Answer:5

Step-by-step explanation:

If you are looking for the distance then start counting on the first decimal and stop at the second

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2 years ago
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