Solution:- Given numbers to compare are 512 and 521 .
As they are 3 digit numbers
So, we have to compare hundreds place.
But hundreds are equal in both the numbers with digit 5.
Next we have to compare tens place.
Case 1 :- 1 ten is smaller in 512 than 2 tens in 521 .
So we get the result that,
512 is smaller than 521
or <em> 512 < 521</em>
Case 2:-2 tens is greater in 521 than 1 ten in 512 .
So we get the result that,
521 is greater than 512
or <em> 521 > 512</em>
Answer:
117.5 or 235/2
Step-by-step explanation:
We can set up an equation for this problem:
Lets Joe's weight be x
then:
2x -5 = 230
therefore:
2x = 235
x = 117.5 or 235/2
Answer:
Exact form: 8![\sqrt[4]{8}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B8%7D)
Decimal form: 13.45434264......
Hoped I Helped
