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Charra [1.4K]
3 years ago
6

Answer plz! Which choices are equivalent to the expression below? Check all that apply.

Mathematics
1 answer:
Tcecarenko [31]3 years ago
3 0

<em>The</em><em> </em><em>right</em><em> </em><em>opti</em><em>ons</em><em> </em><em>are</em><em>:</em>

  • <em>Option</em><em> </em><em>A</em>
  • <em>Option</em><em> </em><em>C</em>
  • <em>Op</em><em>tion</em><em> </em><em>E</em>

<em>ple</em><em>ase</em><em> </em><em>see</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em>

<em>Good</em><em> </em><em>luck</em><em> on</em><em> your</em><em> assignment</em>

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Graph the inequality x&gt;-8 using the steps
Yuki888 [10]
Hey!


Your point on the graph would be ( -8, 0 ).

We shade the right side of the graph because the inequality shows that x is greater than -8.

*SEE THE GRAPH BELOW*

Hope this helps!


- Lindsey Frazier ♥

3 0
3 years ago
HELLOOOO HELP PLEASE
MA_775_DIABLO [31]

Answer:

2*log(x)+log(y)

Step-by-step explanation:

So, there are two logarithmic identities you're going to need to know.

<em>Logarithm of a power</em>:

   log_ba^c=c*log_ba

   So to provide a quick proof and intuition as to why this works, let's consider the following logarithm: log_ba=x\implies b^x=a

   Now if we raise both sides to the power of c, we get the following equation: (b^x)^c=a^c

   Using the exponential identity: (x^a)^c=x^{a*c}

    We get the equation: b^{xc}=a^c

    If we convert this back into logarithmic form we get: log_ba^c=x*c

    Since x was the basic logarithm we started with, we substitute it back in, to get the equation: log_ba^c=c*log_ba

Now the second logarithmic property you need to know is

<em>The Logarithm of a Product</em>:

    log_b{ac}=log_ba+log_bc

    Now for a quick proof, let's just say: x=log_ba\text{ and }y=log_bc

    Now rewriting them both in exponential form, we get the equations:

    b^x=a\\b^y=c

    We can multiply a * c, and since b^x = a, and b^y = c, we can substitute that in for a * c, to get the following equation:

    b^x*b^y=a*c

   Using the exponential identity: x^{a}*x^b=x^{a+b}, we can rewrite the equation as:

 

   b^{x+y}=ac

   taking the logarithm of both sides, we get:

   log_bac=x+y

   Since x and y are just the logarithms we started with, we can substitute them back in to get: log_bac=log_ba+log_bc

Now let's use these identities to rewrite the equation you gave

log(x^2y)

As you can see, this is a log of products, so we can separate it into two logarithms (with the same base)

log(x^2)+log(y)

Now using the logarithm of a power to rewrite the log(x^2) we get:

2*log(x)+log(y)

3 0
2 years ago
Is it true that the constant of the expression 18z-7(-3+2z) is 21
ZanzabumX [31]
Yes. It would be true
7 0
3 years ago
I need help finding the answers to these questions thank you soo much!!!!
anzhelika [568]
Hopefully this helps you ..
3 0
3 years ago
Review the attachments. Review the process of solving an equation and fill in the blanks.
Nezavi [6.7K]

Answer:

1) Combine like terms

2) \sqrt[3]{x} =3

3) cube both sides of the equation

4) 4\sqrt[3]{27} +8\sqrt[3]{27}=36

5) 4(3) + 8(3) = 36

Step-by-step explanation:

1) Combine like terms

2) \sqrt[3]{x} =3

3) cube both sides of the equation

4) 4\sqrt[3]{27} +8\sqrt[3]{27}=36

5) 4(3) + 8(3) = 36

5 0
2 years ago
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